Input interpretation
![lithium diethylamide | molar mass](../image_source/6dc93b3a3b548c0bee7bc8dd1ce777b2.png)
lithium diethylamide | molar mass
Result
![Find the molar mass, M, for lithium diethylamide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_2H_5)_2NLi Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 H (hydrogen) | 10 Li (lithium) | 1 N (nitrogen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 H (hydrogen) | 10 | 1.008 Li (lithium) | 1 | 6.94 N (nitrogen) | 1 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 Li (lithium) | 1 | 6.94 | 1 × 6.94 = 6.94 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 M = 48.044 g/mol + 10.080 g/mol + 6.94 g/mol + 14.007 g/mol = 79.07 g/mol](../image_source/844abe77a19d3c426b10ebcec9059791.png)
Find the molar mass, M, for lithium diethylamide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_2H_5)_2NLi Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 H (hydrogen) | 10 Li (lithium) | 1 N (nitrogen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 H (hydrogen) | 10 | 1.008 Li (lithium) | 1 | 6.94 N (nitrogen) | 1 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 Li (lithium) | 1 | 6.94 | 1 × 6.94 = 6.94 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 M = 48.044 g/mol + 10.080 g/mol + 6.94 g/mol + 14.007 g/mol = 79.07 g/mol
Unit conversion
![0.07907 kg/mol (kilograms per mole)](../image_source/3c2437db77d17b5e0a85f78cc23626ce.png)
0.07907 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.11 ≈ 1/9 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/55e2c26461ebbe4fdca83e4726f48f3d.png)
≈ ( 0.11 ≈ 1/9 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.41 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/d7c04105b53a8734d7ddb1acc658f884.png)
≈ 0.41 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/cdc55423a1f7846c7b96a42cfa5f60d6.png)
≈ 1.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.3×10^-22 grams | 1.3×10^-25 kg (kilograms) | 79 u (unified atomic mass units) | 79 Da (daltons)](../image_source/e0ea5f16dbde0858ca16e49f634c0cd1.png)
Mass of a molecule m from m = M/N_A: | 1.3×10^-22 grams | 1.3×10^-25 kg (kilograms) | 79 u (unified atomic mass units) | 79 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 79](../image_source/c3fa673b236fc1e40cc21e17fc1bceaf.png)
Relative molecular mass M_r from M_r = M_u/M: | 79