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molar mass of ferrous iodide

Input interpretation

ferrous iodide | molar mass
ferrous iodide | molar mass

Result

Find the molar mass, M, for ferrous iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: FeI_2 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Fe (iron) | 1  I (iodine) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Fe (iron) | 1 | 55.845  I (iodine) | 2 | 126.90447 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Fe (iron) | 1 | 55.845 | 1 × 55.845 = 55.845  I (iodine) | 2 | 126.90447 | 2 × 126.90447 = 253.80894  M = 55.845 g/mol + 253.80894 g/mol = 309.654 g/mol
Find the molar mass, M, for ferrous iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: FeI_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Fe (iron) | 1 I (iodine) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Fe (iron) | 1 | 55.845 I (iodine) | 2 | 126.90447 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Fe (iron) | 1 | 55.845 | 1 × 55.845 = 55.845 I (iodine) | 2 | 126.90447 | 2 × 126.90447 = 253.80894 M = 55.845 g/mol + 253.80894 g/mol = 309.654 g/mol

Unit conversion

0.309654 kg/mol (kilograms per mole)
0.309654 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.43 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.43 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 5.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 5.3 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 5.1×10^-22 grams  | 5.1×10^-25 kg (kilograms)  | 310 u (unified atomic mass units)  | 310 Da (daltons)
Mass of a molecule m from m = M/N_A: | 5.1×10^-22 grams | 5.1×10^-25 kg (kilograms) | 310 u (unified atomic mass units) | 310 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 310
Relative molecular mass M_r from M_r = M_u/M: | 310