SO2 + H6TeO6 = H2SO4 + Te

SO_2 (sulfur dioxide) + H_6TeO_6 (telluric(VI) acid) ⟶ H_2SO_4 (sulfuric acid) + Te (tellurium)

Balance the chemical equation algebraically: SO_2 + H_6TeO_6 ⟶ H_2SO_4 + Te Add stoichiometric coefficients, c_i, to the reactants and products: c_1 SO_2 + c_2 H_6TeO_6 ⟶ c_3 H_2SO_4 + c_4 Te Set the number of atoms in the reactants equal to the number of atoms in the products for O, S, H and Te: O: | 2 c_1 + 6 c_2 = 4 c_3 S: | c_1 = c_3 H: | 6 c_2 = 2 c_3 Te: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 SO_2 + H_6TeO_6 ⟶ 3 H_2SO_4 + Te

+ ⟶ +

sulfur dioxide + telluric(VI) acid ⟶ sulfuric acid + tellurium

Construct the equilibrium constant, K, expression for: SO_2 + H_6TeO_6 ⟶ H_2SO_4 + Te Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 SO_2 + H_6TeO_6 ⟶ 3 H_2SO_4 + Te Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_2 | 3 | -3 H_6TeO_6 | 1 | -1 H_2SO_4 | 3 | 3 Te | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression SO_2 | 3 | -3 | ([SO2])^(-3) H_6TeO_6 | 1 | -1 | ([H6TeO6])^(-1) H_2SO_4 | 3 | 3 | ([H2SO4])^3 Te | 1 | 1 | [Te] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([SO2])^(-3) ([H6TeO6])^(-1) ([H2SO4])^3 [Te] = (([H2SO4])^3 [Te])/(([SO2])^3 [H6TeO6])

Construct the rate of reaction expression for: SO_2 + H_6TeO_6 ⟶ H_2SO_4 + Te Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 SO_2 + H_6TeO_6 ⟶ 3 H_2SO_4 + Te Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_2 | 3 | -3 H_6TeO_6 | 1 | -1 H_2SO_4 | 3 | 3 Te | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term SO_2 | 3 | -3 | -1/3 (Δ[SO2])/(Δt) H_6TeO_6 | 1 | -1 | -(Δ[H6TeO6])/(Δt) H_2SO_4 | 3 | 3 | 1/3 (Δ[H2SO4])/(Δt) Te | 1 | 1 | (Δ[Te])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[SO2])/(Δt) = -(Δ[H6TeO6])/(Δt) = 1/3 (Δ[H2SO4])/(Δt) = (Δ[Te])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| sulfur dioxide | telluric(VI) acid | sulfuric acid | tellurium formula | SO_2 | H_6TeO_6 | H_2SO_4 | Te Hill formula | O_2S | H_6O_6Te | H_2O_4S | Te name | sulfur dioxide | telluric(VI) acid | sulfuric acid | tellurium

| sulfur dioxide | telluric(VI) acid | sulfuric acid | tellurium molar mass | 64.06 g/mol | 229.64 g/mol | 98.07 g/mol | 127.6 g/mol phase | gas (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | -73 °C | 136 °C | 10.371 °C | 450 °C boiling point | -10 °C | | 279.6 °C | 990 °C density | 0.002619 g/cm^3 (at 25 °C) | 3.068 g/cm^3 | 1.8305 g/cm^3 | 6.24 g/cm^3 solubility in water | | | very soluble | insoluble surface tension | 0.02859 N/m | | 0.0735 N/m | dynamic viscosity | 1.282×10^-5 Pa s (at 25 °C) | | 0.021 Pa s (at 25 °C) | odor | | | odorless |