Input interpretation
potassium permanganate + ammonia ⟶ water + potassium hydroxide + manganese dioxide + nitrogen
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for K, Mn, O, H and N: K: | c_1 = c_4 Mn: | c_1 = c_5 O: | 4 c_1 = c_3 + c_4 + 2 c_5 H: | 3 c_2 = 2 c_3 + c_4 N: | c_2 = 2 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 2 c_4 = 2 c_5 = 2 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 + 2 ⟶ 2 + 2 + 2 +
Structures
+ ⟶ + + +
Names
potassium permanganate + ammonia ⟶ water + potassium hydroxide + manganese dioxide + nitrogen
Reaction thermodynamics
Gibbs free energy
| potassium permanganate | ammonia | water | potassium hydroxide | manganese dioxide | nitrogen molecular free energy | -737.6 kJ/mol | -16.4 kJ/mol | -237.1 kJ/mol | -379.4 kJ/mol | -465.1 kJ/mol | 0 kJ/mol total free energy | -1475 kJ/mol | -32.8 kJ/mol | -474.2 kJ/mol | -758.8 kJ/mol | -930.2 kJ/mol | 0 kJ/mol | G_initial = -1508 kJ/mol | | G_final = -2163 kJ/mol | | | ΔG_rxn^0 | -2163 kJ/mol - -1508 kJ/mol = -655.2 kJ/mol (exergonic) | | | | |
Chemical names and formulas
| potassium permanganate | ammonia | water | potassium hydroxide | manganese dioxide | nitrogen Hill formula | KMnO_4 | H_3N | H_2O | HKO | MnO_2 | N_2 name | potassium permanganate | ammonia | water | potassium hydroxide | manganese dioxide | nitrogen IUPAC name | potassium permanganate | ammonia | water | potassium hydroxide | dioxomanganese | molecular nitrogen