Search

KOH + ReCl6 = H2O + KCl + ReO2 + KReO4

Input interpretation

KOH potassium hydroxide + ReCl_6 rhenium(VI) chloride ⟶ H_2O water + KCl potassium chloride + ReO_2 rhenium oxide + KReO_4 potassium perrhenate
KOH potassium hydroxide + ReCl_6 rhenium(VI) chloride ⟶ H_2O water + KCl potassium chloride + ReO_2 rhenium oxide + KReO_4 potassium perrhenate

Balanced equation

Balance the chemical equation algebraically: KOH + ReCl_6 ⟶ H_2O + KCl + ReO_2 + KReO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 ReCl_6 ⟶ c_3 H_2O + c_4 KCl + c_5 ReO_2 + c_6 KReO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cl and Re: H: | c_1 = 2 c_3 K: | c_1 = c_4 + c_6 O: | c_1 = c_3 + 2 c_5 + 4 c_6 Cl: | 6 c_2 = c_4 Re: | c_2 = c_5 + c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 20 c_2 = 3 c_3 = 10 c_4 = 18 c_5 = 1 c_6 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 20 KOH + 3 ReCl_6 ⟶ 10 H_2O + 18 KCl + ReO_2 + 2 KReO_4
Balance the chemical equation algebraically: KOH + ReCl_6 ⟶ H_2O + KCl + ReO_2 + KReO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 ReCl_6 ⟶ c_3 H_2O + c_4 KCl + c_5 ReO_2 + c_6 KReO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Cl and Re: H: | c_1 = 2 c_3 K: | c_1 = c_4 + c_6 O: | c_1 = c_3 + 2 c_5 + 4 c_6 Cl: | 6 c_2 = c_4 Re: | c_2 = c_5 + c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 20 c_2 = 3 c_3 = 10 c_4 = 18 c_5 = 1 c_6 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 20 KOH + 3 ReCl_6 ⟶ 10 H_2O + 18 KCl + ReO_2 + 2 KReO_4

Structures

+ ⟶ + + +
+ ⟶ + + +

Names

potassium hydroxide + rhenium(VI) chloride ⟶ water + potassium chloride + rhenium oxide + potassium perrhenate
potassium hydroxide + rhenium(VI) chloride ⟶ water + potassium chloride + rhenium oxide + potassium perrhenate

Equilibrium constant

Construct the equilibrium constant, K, expression for: KOH + ReCl_6 ⟶ H_2O + KCl + ReO_2 + KReO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 20 KOH + 3 ReCl_6 ⟶ 10 H_2O + 18 KCl + ReO_2 + 2 KReO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 20 | -20 ReCl_6 | 3 | -3 H_2O | 10 | 10 KCl | 18 | 18 ReO_2 | 1 | 1 KReO_4 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 20 | -20 | ([KOH])^(-20) ReCl_6 | 3 | -3 | ([ReCl6])^(-3) H_2O | 10 | 10 | ([H2O])^10 KCl | 18 | 18 | ([KCl])^18 ReO_2 | 1 | 1 | [ReO2] KReO_4 | 2 | 2 | ([KReO4])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-20) ([ReCl6])^(-3) ([H2O])^10 ([KCl])^18 [ReO2] ([KReO4])^2 = (([H2O])^10 ([KCl])^18 [ReO2] ([KReO4])^2)/(([KOH])^20 ([ReCl6])^3)
Construct the equilibrium constant, K, expression for: KOH + ReCl_6 ⟶ H_2O + KCl + ReO_2 + KReO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 20 KOH + 3 ReCl_6 ⟶ 10 H_2O + 18 KCl + ReO_2 + 2 KReO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 20 | -20 ReCl_6 | 3 | -3 H_2O | 10 | 10 KCl | 18 | 18 ReO_2 | 1 | 1 KReO_4 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 20 | -20 | ([KOH])^(-20) ReCl_6 | 3 | -3 | ([ReCl6])^(-3) H_2O | 10 | 10 | ([H2O])^10 KCl | 18 | 18 | ([KCl])^18 ReO_2 | 1 | 1 | [ReO2] KReO_4 | 2 | 2 | ([KReO4])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-20) ([ReCl6])^(-3) ([H2O])^10 ([KCl])^18 [ReO2] ([KReO4])^2 = (([H2O])^10 ([KCl])^18 [ReO2] ([KReO4])^2)/(([KOH])^20 ([ReCl6])^3)

Rate of reaction

Construct the rate of reaction expression for: KOH + ReCl_6 ⟶ H_2O + KCl + ReO_2 + KReO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 20 KOH + 3 ReCl_6 ⟶ 10 H_2O + 18 KCl + ReO_2 + 2 KReO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 20 | -20 ReCl_6 | 3 | -3 H_2O | 10 | 10 KCl | 18 | 18 ReO_2 | 1 | 1 KReO_4 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 20 | -20 | -1/20 (Δ[KOH])/(Δt) ReCl_6 | 3 | -3 | -1/3 (Δ[ReCl6])/(Δt) H_2O | 10 | 10 | 1/10 (Δ[H2O])/(Δt) KCl | 18 | 18 | 1/18 (Δ[KCl])/(Δt) ReO_2 | 1 | 1 | (Δ[ReO2])/(Δt) KReO_4 | 2 | 2 | 1/2 (Δ[KReO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/20 (Δ[KOH])/(Δt) = -1/3 (Δ[ReCl6])/(Δt) = 1/10 (Δ[H2O])/(Δt) = 1/18 (Δ[KCl])/(Δt) = (Δ[ReO2])/(Δt) = 1/2 (Δ[KReO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: KOH + ReCl_6 ⟶ H_2O + KCl + ReO_2 + KReO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 20 KOH + 3 ReCl_6 ⟶ 10 H_2O + 18 KCl + ReO_2 + 2 KReO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 20 | -20 ReCl_6 | 3 | -3 H_2O | 10 | 10 KCl | 18 | 18 ReO_2 | 1 | 1 KReO_4 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 20 | -20 | -1/20 (Δ[KOH])/(Δt) ReCl_6 | 3 | -3 | -1/3 (Δ[ReCl6])/(Δt) H_2O | 10 | 10 | 1/10 (Δ[H2O])/(Δt) KCl | 18 | 18 | 1/18 (Δ[KCl])/(Δt) ReO_2 | 1 | 1 | (Δ[ReO2])/(Δt) KReO_4 | 2 | 2 | 1/2 (Δ[KReO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/20 (Δ[KOH])/(Δt) = -1/3 (Δ[ReCl6])/(Δt) = 1/10 (Δ[H2O])/(Δt) = 1/18 (Δ[KCl])/(Δt) = (Δ[ReO2])/(Δt) = 1/2 (Δ[KReO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| potassium hydroxide | rhenium(VI) chloride | water | potassium chloride | rhenium oxide | potassium perrhenate formula | KOH | ReCl_6 | H_2O | KCl | ReO_2 | KReO_4 Hill formula | HKO | Cl_6Re_1 | H_2O | ClK | O_2Re | KO_4Re name | potassium hydroxide | rhenium(VI) chloride | water | potassium chloride | rhenium oxide | potassium perrhenate IUPAC name | potassium hydroxide | | water | potassium chloride | dioxorhenium | potassium oxido-trioxorhenium
| potassium hydroxide | rhenium(VI) chloride | water | potassium chloride | rhenium oxide | potassium perrhenate formula | KOH | ReCl_6 | H_2O | KCl | ReO_2 | KReO_4 Hill formula | HKO | Cl_6Re_1 | H_2O | ClK | O_2Re | KO_4Re name | potassium hydroxide | rhenium(VI) chloride | water | potassium chloride | rhenium oxide | potassium perrhenate IUPAC name | potassium hydroxide | | water | potassium chloride | dioxorhenium | potassium oxido-trioxorhenium

Substance properties

| potassium hydroxide | rhenium(VI) chloride | water | potassium chloride | rhenium oxide | potassium perrhenate molar mass | 56.105 g/mol | 398.9 g/mol | 18.015 g/mol | 74.55 g/mol | 218.205 g/mol | 289.301 g/mol phase | solid (at STP) | | liquid (at STP) | solid (at STP) | | solid (at STP) melting point | 406 °C | 29 °C | 0 °C | 770 °C | | 550 °C boiling point | 1327 °C | | 99.9839 °C | 1420 °C | | density | 2.044 g/cm^3 | | 1 g/cm^3 | 1.98 g/cm^3 | 11.4 g/cm^3 | 4.887 g/cm^3 solubility in water | soluble | | | soluble | insoluble | surface tension | | | 0.0728 N/m | | | dynamic viscosity | 0.001 Pa s (at 550 °C) | | 8.9×10^-4 Pa s (at 25 °C) | | | odor | | | odorless | odorless | |
| potassium hydroxide | rhenium(VI) chloride | water | potassium chloride | rhenium oxide | potassium perrhenate molar mass | 56.105 g/mol | 398.9 g/mol | 18.015 g/mol | 74.55 g/mol | 218.205 g/mol | 289.301 g/mol phase | solid (at STP) | | liquid (at STP) | solid (at STP) | | solid (at STP) melting point | 406 °C | 29 °C | 0 °C | 770 °C | | 550 °C boiling point | 1327 °C | | 99.9839 °C | 1420 °C | | density | 2.044 g/cm^3 | | 1 g/cm^3 | 1.98 g/cm^3 | 11.4 g/cm^3 | 4.887 g/cm^3 solubility in water | soluble | | | soluble | insoluble | surface tension | | | 0.0728 N/m | | | dynamic viscosity | 0.001 Pa s (at 550 °C) | | 8.9×10^-4 Pa s (at 25 °C) | | | odor | | | odorless | odorless | |

Units

Random Queries

CAS number of acetic acid vs water
discovery year of sodium vs lithium
CAS number of 3-ethylhexane
CAS number of silver iodate vs beryllium
freezing point of strontium niobate vs strontium nitrate
U-236 vs Pa-227 vs Bi-209
molar mass of potassium selenide vs antimony(III) butoxide
Aufbau diagram of super-heavy elements
element types of potassium aminetrichloroplatinate(II) vs antimony(III) telluride
AgNO3 + ZnBr2 = Zn(NO3)2 + AgBr