Input interpretation
![24(25)-dihydrocycloartenol | molar mass](../image_source/75399d6d7995c11672569447258e5852.png)
24(25)-dihydrocycloartenol | molar mass
Result
![Find the molar mass, M, for 24(25)-dihydrocycloartenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_29H_50O_1 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 30 H (hydrogen) | 52 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 30 | 12.011 H (hydrogen) | 52 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 30 | 12.011 | 30 × 12.011 = 360.330 H (hydrogen) | 52 | 1.008 | 52 × 1.008 = 52.416 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 360.330 g/mol + 52.416 g/mol + 15.999 g/mol = 428.745 g/mol](../image_source/95d570de906e984457541dbda4e5c4e3.png)
Find the molar mass, M, for 24(25)-dihydrocycloartenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_29H_50O_1 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 30 H (hydrogen) | 52 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 30 | 12.011 H (hydrogen) | 52 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 30 | 12.011 | 30 × 12.011 = 360.330 H (hydrogen) | 52 | 1.008 | 52 × 1.008 = 52.416 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 360.330 g/mol + 52.416 g/mol + 15.999 g/mol = 428.745 g/mol
Unit conversion
![0.42875 kg/mol (kilograms per mole)](../image_source/dfc4af5dda19cb64c6fb25cb331f1e5a.png)
0.42875 kg/mol (kilograms per mole)
Comparisons
![≈ 0.59 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/5a98a565e0109a6ea4519ad29e25f70b.png)
≈ 0.59 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/11f7717caf2895a895ed8c27441a081e.png)
≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/93365ab43bb59180949184d3aa96f318.png)
≈ 7.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7.1×10^-22 grams | 7.1×10^-25 kg (kilograms) | 429 u (unified atomic mass units) | 429 Da (daltons)](../image_source/6d91aa26430138da2077101b1d5c33bc.png)
Mass of a molecule m from m = M/N_A: | 7.1×10^-22 grams | 7.1×10^-25 kg (kilograms) | 429 u (unified atomic mass units) | 429 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 429](../image_source/d88f6469d0f5db369342643b2ad81870.png)
Relative molecular mass M_r from M_r = M_u/M: | 429