Input interpretation
![Cl_2 chlorine + FeSO_4 duretter ⟶ FeCl_3 iron(III) chloride + Fe_2(SO_4)_3·xH_2O iron(III) sulfate hydrate](../image_source/e5d0fee9d649de44866f8ceb612b385d.png)
Cl_2 chlorine + FeSO_4 duretter ⟶ FeCl_3 iron(III) chloride + Fe_2(SO_4)_3·xH_2O iron(III) sulfate hydrate
Balanced equation
![Balance the chemical equation algebraically: Cl_2 + FeSO_4 ⟶ FeCl_3 + Fe_2(SO_4)_3·xH_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cl_2 + c_2 FeSO_4 ⟶ c_3 FeCl_3 + c_4 Fe_2(SO_4)_3·xH_2O Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, Fe, O and S: Cl: | 2 c_1 = 3 c_3 Fe: | c_2 = c_3 + 2 c_4 O: | 4 c_2 = 12 c_4 S: | c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 3 c_3 = 1 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 6 c_3 = 2 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 Cl_2 + 6 FeSO_4 ⟶ 2 FeCl_3 + 2 Fe_2(SO_4)_3·xH_2O](../image_source/b2e1649f23b9d7dd338e6d3a54284a82.png)
Balance the chemical equation algebraically: Cl_2 + FeSO_4 ⟶ FeCl_3 + Fe_2(SO_4)_3·xH_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cl_2 + c_2 FeSO_4 ⟶ c_3 FeCl_3 + c_4 Fe_2(SO_4)_3·xH_2O Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, Fe, O and S: Cl: | 2 c_1 = 3 c_3 Fe: | c_2 = c_3 + 2 c_4 O: | 4 c_2 = 12 c_4 S: | c_2 = 3 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 3 c_3 = 1 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 6 c_3 = 2 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 Cl_2 + 6 FeSO_4 ⟶ 2 FeCl_3 + 2 Fe_2(SO_4)_3·xH_2O
Structures
![+ ⟶ +](../image_source/654fa80bbee87e225e3d74af81b87e9a.png)
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Names
![chlorine + duretter ⟶ iron(III) chloride + iron(III) sulfate hydrate](../image_source/ba93a9c60f82fdb8ed4bd4cbf14c9523.png)
chlorine + duretter ⟶ iron(III) chloride + iron(III) sulfate hydrate
Equilibrium constant
![Construct the equilibrium constant, K, expression for: Cl_2 + FeSO_4 ⟶ FeCl_3 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 Cl_2 + 6 FeSO_4 ⟶ 2 FeCl_3 + 2 Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 3 | -3 FeSO_4 | 6 | -6 FeCl_3 | 2 | 2 Fe_2(SO_4)_3·xH_2O | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cl_2 | 3 | -3 | ([Cl2])^(-3) FeSO_4 | 6 | -6 | ([FeSO4])^(-6) FeCl_3 | 2 | 2 | ([FeCl3])^2 Fe_2(SO_4)_3·xH_2O | 2 | 2 | ([Fe2(SO4)3·xH2O])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Cl2])^(-3) ([FeSO4])^(-6) ([FeCl3])^2 ([Fe2(SO4)3·xH2O])^2 = (([FeCl3])^2 ([Fe2(SO4)3·xH2O])^2)/(([Cl2])^3 ([FeSO4])^6)](../image_source/1966b71bacf8dfc490c45a874bb087fd.png)
Construct the equilibrium constant, K, expression for: Cl_2 + FeSO_4 ⟶ FeCl_3 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 Cl_2 + 6 FeSO_4 ⟶ 2 FeCl_3 + 2 Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 3 | -3 FeSO_4 | 6 | -6 FeCl_3 | 2 | 2 Fe_2(SO_4)_3·xH_2O | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cl_2 | 3 | -3 | ([Cl2])^(-3) FeSO_4 | 6 | -6 | ([FeSO4])^(-6) FeCl_3 | 2 | 2 | ([FeCl3])^2 Fe_2(SO_4)_3·xH_2O | 2 | 2 | ([Fe2(SO4)3·xH2O])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Cl2])^(-3) ([FeSO4])^(-6) ([FeCl3])^2 ([Fe2(SO4)3·xH2O])^2 = (([FeCl3])^2 ([Fe2(SO4)3·xH2O])^2)/(([Cl2])^3 ([FeSO4])^6)
Rate of reaction
![Construct the rate of reaction expression for: Cl_2 + FeSO_4 ⟶ FeCl_3 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 Cl_2 + 6 FeSO_4 ⟶ 2 FeCl_3 + 2 Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 3 | -3 FeSO_4 | 6 | -6 FeCl_3 | 2 | 2 Fe_2(SO_4)_3·xH_2O | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cl_2 | 3 | -3 | -1/3 (Δ[Cl2])/(Δt) FeSO_4 | 6 | -6 | -1/6 (Δ[FeSO4])/(Δt) FeCl_3 | 2 | 2 | 1/2 (Δ[FeCl3])/(Δt) Fe_2(SO_4)_3·xH_2O | 2 | 2 | 1/2 (Δ[Fe2(SO4)3·xH2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[Cl2])/(Δt) = -1/6 (Δ[FeSO4])/(Δt) = 1/2 (Δ[FeCl3])/(Δt) = 1/2 (Δ[Fe2(SO4)3·xH2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/bf1f7b479ed4f9072fbb2255eac04525.png)
Construct the rate of reaction expression for: Cl_2 + FeSO_4 ⟶ FeCl_3 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 Cl_2 + 6 FeSO_4 ⟶ 2 FeCl_3 + 2 Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 3 | -3 FeSO_4 | 6 | -6 FeCl_3 | 2 | 2 Fe_2(SO_4)_3·xH_2O | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cl_2 | 3 | -3 | -1/3 (Δ[Cl2])/(Δt) FeSO_4 | 6 | -6 | -1/6 (Δ[FeSO4])/(Δt) FeCl_3 | 2 | 2 | 1/2 (Δ[FeCl3])/(Δt) Fe_2(SO_4)_3·xH_2O | 2 | 2 | 1/2 (Δ[Fe2(SO4)3·xH2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[Cl2])/(Δt) = -1/6 (Δ[FeSO4])/(Δt) = 1/2 (Δ[FeCl3])/(Δt) = 1/2 (Δ[Fe2(SO4)3·xH2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| chlorine | duretter | iron(III) chloride | iron(III) sulfate hydrate formula | Cl_2 | FeSO_4 | FeCl_3 | Fe_2(SO_4)_3·xH_2O Hill formula | Cl_2 | FeO_4S | Cl_3Fe | Fe_2O_12S_3 name | chlorine | duretter | iron(III) chloride | iron(III) sulfate hydrate IUPAC name | molecular chlorine | iron(+2) cation sulfate | trichloroiron | diferric trisulfate](../image_source/e0a8f81fc7c2bd6eccc5839c4b4d78d0.png)
| chlorine | duretter | iron(III) chloride | iron(III) sulfate hydrate formula | Cl_2 | FeSO_4 | FeCl_3 | Fe_2(SO_4)_3·xH_2O Hill formula | Cl_2 | FeO_4S | Cl_3Fe | Fe_2O_12S_3 name | chlorine | duretter | iron(III) chloride | iron(III) sulfate hydrate IUPAC name | molecular chlorine | iron(+2) cation sulfate | trichloroiron | diferric trisulfate
Substance properties
![| chlorine | duretter | iron(III) chloride | iron(III) sulfate hydrate molar mass | 70.9 g/mol | 151.9 g/mol | 162.2 g/mol | 399.9 g/mol phase | gas (at STP) | | solid (at STP) | melting point | -101 °C | | 304 °C | boiling point | -34 °C | | | density | 0.003214 g/cm^3 (at 0 °C) | 2.841 g/cm^3 | | solubility in water | | | | slightly soluble](../image_source/6c3d369d54fd07e2f6607714253fffcf.png)
| chlorine | duretter | iron(III) chloride | iron(III) sulfate hydrate molar mass | 70.9 g/mol | 151.9 g/mol | 162.2 g/mol | 399.9 g/mol phase | gas (at STP) | | solid (at STP) | melting point | -101 °C | | 304 °C | boiling point | -34 °C | | | density | 0.003214 g/cm^3 (at 0 °C) | 2.841 g/cm^3 | | solubility in water | | | | slightly soluble
Units