Input interpretation
![thulium(III) oxalate hexahydrate | molar mass](../image_source/d58c071ca50d27f3f71f0da9ab7ac710.png)
thulium(III) oxalate hexahydrate | molar mass
Result
![Find the molar mass, M, for thulium(III) oxalate hexahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Tm_2(C_2O_4)_3·6H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 12 O (oxygen) | 18 Tm (thulium) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 H (hydrogen) | 12 | 1.008 O (oxygen) | 18 | 15.999 Tm (thulium) | 2 | 168.93422 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 18 | 15.999 | 18 × 15.999 = 287.982 Tm (thulium) | 2 | 168.93422 | 2 × 168.93422 = 337.86844 M = 72.066 g/mol + 12.096 g/mol + 287.982 g/mol + 337.86844 g/mol = 710.012 g/mol](../image_source/1e39b8962bb3afa7ba714a4a9367d37d.png)
Find the molar mass, M, for thulium(III) oxalate hexahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Tm_2(C_2O_4)_3·6H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 12 O (oxygen) | 18 Tm (thulium) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 H (hydrogen) | 12 | 1.008 O (oxygen) | 18 | 15.999 Tm (thulium) | 2 | 168.93422 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 18 | 15.999 | 18 × 15.999 = 287.982 Tm (thulium) | 2 | 168.93422 | 2 × 168.93422 = 337.86844 M = 72.066 g/mol + 12.096 g/mol + 287.982 g/mol + 337.86844 g/mol = 710.012 g/mol
Unit conversion
![0.71001 kg/mol (kilograms per mole)](../image_source/ffbdc7193ca319e4cac7df9ab5d6898a.png)
0.71001 kg/mol (kilograms per mole)
Comparisons
![≈ 0.99 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/459cfc3247827e62b31d8aca8a6844f9.png)
≈ 0.99 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 3.7 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/fa4384bb24dfae46fc99528f537c3952.png)
≈ 3.7 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 12 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/ff1152cb1b4c9f4159ce543e7445601f.png)
≈ 12 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.2×10^-21 grams | 1.2×10^-24 kg (kilograms) | 710 u (unified atomic mass units) | 710 Da (daltons)](../image_source/6aa16787aba5ef4ed17f9bd76fd20570.png)
Mass of a molecule m from m = M/N_A: | 1.2×10^-21 grams | 1.2×10^-24 kg (kilograms) | 710 u (unified atomic mass units) | 710 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 710](../image_source/4ff97f945849d1970dfab3c6e8359394.png)
Relative molecular mass M_r from M_r = M_u/M: | 710