Input interpretation
![propantheline bromide | molar mass](../image_source/9b66826b7a5ad909c1e158b9b5f76374.png)
propantheline bromide | molar mass
Result
![Find the molar mass, M, for propantheline bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_23H_30NO_3Br Use the chemical formula, C_23H_30NO_3Br, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 23 H (hydrogen) | 30 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 23 | 12.011 H (hydrogen) | 30 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 23 | 12.011 | 23 × 12.011 = 276.253 H (hydrogen) | 30 | 1.008 | 30 × 1.008 = 30.240 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 79.904 g/mol + 276.253 g/mol + 30.240 g/mol + 14.007 g/mol + 47.997 g/mol = 448.401 g/mol](../image_source/4b170fa81428ee49366749396b25d1fe.png)
Find the molar mass, M, for propantheline bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_23H_30NO_3Br Use the chemical formula, C_23H_30NO_3Br, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 23 H (hydrogen) | 30 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 23 | 12.011 H (hydrogen) | 30 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 23 | 12.011 | 23 × 12.011 = 276.253 H (hydrogen) | 30 | 1.008 | 30 × 1.008 = 30.240 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 79.904 g/mol + 276.253 g/mol + 30.240 g/mol + 14.007 g/mol + 47.997 g/mol = 448.401 g/mol
Unit conversion
![0.4484 kg/mol (kilograms per mole)](../image_source/9002206255c09a0edcd2726a13e75a93.png)
0.4484 kg/mol (kilograms per mole)
Comparisons
![≈ 0.62 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/ca59cc4002fafd9776787f75dfd5c986.png)
≈ 0.62 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/6466232d5859e53ccaf3e6ce23c1eeee.png)
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/560c9ca99708914bd7287c0eb0e03f90.png)
≈ 7.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7.4×10^-22 grams | 7.4×10^-25 kg (kilograms) | 448 u (unified atomic mass units) | 448 Da (daltons)](../image_source/1b98c3bf7b9ec09b002dfc12a8eee6d2.png)
Mass of a molecule m from m = M/N_A: | 7.4×10^-22 grams | 7.4×10^-25 kg (kilograms) | 448 u (unified atomic mass units) | 448 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 448](../image_source/62404b0e6fb778155acfafb687ed78a4.png)
Relative molecular mass M_r from M_r = M_u/M: | 448