Input interpretation
convert 12 kg of nickel (chemical element) to volume
Results
1.347 L (liters)
Possible intermediate steps
Convert from kilograms into liters: 12 kg of Ni (nickel) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 8.908 g/cm^3 (grams per cubic centimeter) at STP of Ni: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(8.908 g) = 1347 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (1347 cm^3)/1 × (1 mL)/(1 cm^3) = 1347 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: | | (1347 mL)/1 × (1 L)/(1000 mL) = 1.347 L
Unit conversions
0.001347 m^3 (cubic meters)
1347 cm^3 (cubic centimeters)
45.55 fl oz (fluid ounces)
2.847 pints
1.423 quarts
0.3559 gallons
0.04757 ft^3 (cubic feet)
82.21 in^3 (cubic inches)
Comparisons as volume
≈ ( 0.06 ≈ 1/17 ) × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
≈ 3 × volume of a typical human breath ( ≈ 0.5 L )
≈ 21 × volume of an Apple iPhone 4 ( ≈ 6.3×10^-5 m^3 )
Comparisons as volume of food or beverage
≈ 0.43 × volume of a US size 10 can ( 105 fl oz )
≈ 0.81 × volume of a US size 5 can ( 7 cups )
≈ 1.4 × volume of a US size 3 can ( 4 cups )
Interpretations
volume
volume of food or beverage
section modulus
Basic unit dimensions
![[length]^3](../image_source/6fb286790ab6cb1623bd7e7dca53989f.png)
[length]^3
Corresponding quantities
Radius r of a sphere from V = 4πr^3/3: | 69 mm (millimeters) | 0.22 feet | 2.7 inches
Edge length a of a cube from V = a^3: | 11 cm (centimeters) | 0.36 feet | 4.3 inches
Mass m of water from m = ρ_(H_2O)V: | 1.3 kg (kilograms) | 3 lb (pounds) | (assuming maximum water density ≈ 1000 kg/m^3)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O): | 4.503×10^25 molecules | (assuming maximum water density ≈ 1000 kg/m^3) | (assuming molecular mass of water ≈ 18.02 u)