Input interpretation
acarbose | molar mass
Result
Find the molar mass, M, for acarbose: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_25H_43NO_18 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 25 H (hydrogen) | 43 N (nitrogen) | 1 O (oxygen) | 18 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 25 | 12.011 H (hydrogen) | 43 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 18 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 25 | 12.011 | 25 × 12.011 = 300.275 H (hydrogen) | 43 | 1.008 | 43 × 1.008 = 43.344 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 18 | 15.999 | 18 × 15.999 = 287.982 M = 300.275 g/mol + 43.344 g/mol + 14.007 g/mol + 287.982 g/mol = 645.608 g/mol
Unit conversion
0.6456 kg/mol (kilograms per mole)
Comparisons
≈ 0.9 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 3.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 11 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1.1×10^-21 grams | 1.1×10^-24 kg (kilograms) | 646 u (unified atomic mass units) | 646 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 646