Input interpretation
![xanthommatin | molar mass](../image_source/bc668d3b7ab453e8443d7616a177bc78.png)
xanthommatin | molar mass
Result
![Find the molar mass, M, for xanthommatin: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_20H_13N_3O_8 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 20 H (hydrogen) | 8 N (nitrogen) | 3 O (oxygen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 20 | 12.011 H (hydrogen) | 8 | 1.008 N (nitrogen) | 3 | 14.007 O (oxygen) | 8 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 20 | 12.011 | 20 × 12.011 = 240.220 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 M = 240.220 g/mol + 8.064 g/mol + 42.021 g/mol + 127.992 g/mol = 418.297 g/mol](../image_source/584117af309de2226b0b03ccebdf7762.png)
Find the molar mass, M, for xanthommatin: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_20H_13N_3O_8 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 20 H (hydrogen) | 8 N (nitrogen) | 3 O (oxygen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 20 | 12.011 H (hydrogen) | 8 | 1.008 N (nitrogen) | 3 | 14.007 O (oxygen) | 8 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 20 | 12.011 | 20 × 12.011 = 240.220 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 M = 240.220 g/mol + 8.064 g/mol + 42.021 g/mol + 127.992 g/mol = 418.297 g/mol
Unit conversion
![0.4183 kg/mol (kilograms per mole)](../image_source/313f5035edf5aa13428a1424e88bc6c1.png)
0.4183 kg/mol (kilograms per mole)
Comparisons
![≈ 0.58 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/d31e2a89acce5f23bddeaa827d632308.png)
≈ 0.58 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/a4a1171c68684ec019b74c787ab19b6b.png)
≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.2 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/6e4af39eda7db035f73311db45b51a78.png)
≈ 7.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6.9×10^-22 grams | 6.9×10^-25 kg (kilograms) | 418 u (unified atomic mass units) | 418 Da (daltons)](../image_source/93b2ad02a4494dfa5d608fc1b599ee73.png)
Mass of a molecule m from m = M/N_A: | 6.9×10^-22 grams | 6.9×10^-25 kg (kilograms) | 418 u (unified atomic mass units) | 418 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 418](../image_source/418810853c6fbadf8d208a4a3475e797.png)
Relative molecular mass M_r from M_r = M_u/M: | 418