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molar mass of propadiene

Input interpretation

propadiene | molar mass
propadiene | molar mass

Result

Find the molar mass, M, for propadiene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2C=C=CH_2 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 3  H (hydrogen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 3 | 12.011  H (hydrogen) | 4 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033  H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032  M = 36.033 g/mol + 4.032 g/mol = 40.065 g/mol
Find the molar mass, M, for propadiene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2C=C=CH_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 3 H (hydrogen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 3 | 12.011 H (hydrogen) | 4 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 3 | 12.011 | 3 × 12.011 = 36.033 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 M = 36.033 g/mol + 4.032 g/mol = 40.065 g/mol

Unit conversion

0.040065 kg/mol (kilograms per mole)
0.040065 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.056 ≈ 1/18 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.056 ≈ 1/18 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ ( 0.21 ≈ 1/5 ) × molar mass of caffeine ( ≈ 194 g/mol )
≈ ( 0.21 ≈ 1/5 ) × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 0.69 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 0.69 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 6.7×10^-23 grams  | 6.7×10^-26 kg (kilograms)  | 40 u (unified atomic mass units)  | 40 Da (daltons)
Mass of a molecule m from m = M/N_A: | 6.7×10^-23 grams | 6.7×10^-26 kg (kilograms) | 40 u (unified atomic mass units) | 40 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 40
Relative molecular mass M_r from M_r = M_u/M: | 40