Input interpretation
thorium(IV) bromide | molar mass
Result
Find the molar mass, M, for thorium(IV) bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Br_4Th Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 4 Th (thorium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 4 | 79.904 Th (thorium) | 1 | 232.0377 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 4 | 79.904 | 4 × 79.904 = 319.616 Th (thorium) | 1 | 232.0377 | 1 × 232.0377 = 232.0377 M = 319.616 g/mol + 232.0377 g/mol = 551.654 g/mol
Unit conversion
0.55165 kg/mol (kilograms per mole)
Comparisons
≈ 0.77 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.8 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 9.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 9.2×10^-22 grams | 9.2×10^-25 kg (kilograms) | 552 u (unified atomic mass units) | 552 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 552