Input interpretation
![water + potassium permanganate + sodium sulfide ⟶ sodium hydroxide + mixed sulfur + potassium hydroxide + manganese dioxide](../image_source/e902ff84a278e8275d8a6a6d66f7ae1a.png)
water + potassium permanganate + sodium sulfide ⟶ sodium hydroxide + mixed sulfur + potassium hydroxide + manganese dioxide
Balanced equation
![Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, K, Mn, Na and S: H: | 2 c_1 = c_4 + c_6 O: | c_1 + 4 c_2 = c_4 + c_6 + 2 c_7 K: | c_2 = c_6 Mn: | c_2 = c_7 Na: | 2 c_3 = c_4 S: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 3/2 c_4 = 3 c_5 = 3/2 c_6 = 1 c_7 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 4 c_2 = 2 c_3 = 3 c_4 = 6 c_5 = 3 c_6 = 2 c_7 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + 2 + 3 ⟶ 6 + 3 + 2 + 2](../image_source/0c83131c7a97b87887b4b3590a0dd6e9.png)
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, K, Mn, Na and S: H: | 2 c_1 = c_4 + c_6 O: | c_1 + 4 c_2 = c_4 + c_6 + 2 c_7 K: | c_2 = c_6 Mn: | c_2 = c_7 Na: | 2 c_3 = c_4 S: | c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 3/2 c_4 = 3 c_5 = 3/2 c_6 = 1 c_7 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 4 c_2 = 2 c_3 = 3 c_4 = 6 c_5 = 3 c_6 = 2 c_7 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + 2 + 3 ⟶ 6 + 3 + 2 + 2
Structures
![+ + ⟶ + + +](../image_source/d8380f3d33a566302d3a19055db974b9.png)
+ + ⟶ + + +
Names
![water + potassium permanganate + sodium sulfide ⟶ sodium hydroxide + mixed sulfur + potassium hydroxide + manganese dioxide](../image_source/822c41a2a8a6b63ad756739cfa37c1e1.png)
water + potassium permanganate + sodium sulfide ⟶ sodium hydroxide + mixed sulfur + potassium hydroxide + manganese dioxide
Chemical names and formulas
![| water | potassium permanganate | sodium sulfide | sodium hydroxide | mixed sulfur | potassium hydroxide | manganese dioxide Hill formula | H_2O | KMnO_4 | Na_2S | HNaO | S | HKO | MnO_2 name | water | potassium permanganate | sodium sulfide | sodium hydroxide | mixed sulfur | potassium hydroxide | manganese dioxide IUPAC name | water | potassium permanganate | | sodium hydroxide | sulfur | potassium hydroxide | dioxomanganese](../image_source/4a446a99f0d1370a96d8e58471f53b2c.png)
| water | potassium permanganate | sodium sulfide | sodium hydroxide | mixed sulfur | potassium hydroxide | manganese dioxide Hill formula | H_2O | KMnO_4 | Na_2S | HNaO | S | HKO | MnO_2 name | water | potassium permanganate | sodium sulfide | sodium hydroxide | mixed sulfur | potassium hydroxide | manganese dioxide IUPAC name | water | potassium permanganate | | sodium hydroxide | sulfur | potassium hydroxide | dioxomanganese