Input interpretation
lead(IV) acetate | molecular mass
Result
Find the molecular mass, m, for lead(IV) acetate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pb(CH_3CO_2)_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 H (hydrogen) | 12 O (oxygen) | 8 Pb (lead) | 1 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 8 | 12.011 H (hydrogen) | 12 | 1.008 O (oxygen) | 8 | 15.999 Pb (lead) | 1 | 207.2 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 Pb (lead) | 1 | 207.2 | 1 × 207.2 = 207.2 m = 96.088 u + 12.096 u + 127.992 u + 207.2 u = 443.4 u
Unit conversions
443.4 Da (daltons)
0.4434 kDa (kilodaltons)
7.362×10^-22 grams
7.362×10^-25 kg (kilograms)
443.4 chemical atomic mass units (unit officially deprecated)
443.5 physical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
≈ 0.62 × molecular mass of fullerene ( ≈ 721 u )
≈ 2.3 × molecular mass of caffeine ( ≈ 194 u )
≈ 7.6 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 443
Molar mass M from M = m_aN_A: | 443 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 443
Molar mass M from M = m_mN_A: | 443 g/mol (grams per mole)