Input interpretation
sodium hydroxide + acetic acid ⟶ water + sodium acetate
Balanced equation
Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O and C: H: | c_1 + 4 c_2 = 2 c_3 + 3 c_4 Na: | c_1 = c_4 O: | c_1 + 2 c_2 = c_3 + 2 c_4 C: | 2 c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | + ⟶ +
Structures
+ ⟶ +
Names
sodium hydroxide + acetic acid ⟶ water + sodium acetate
Reaction thermodynamics
Gibbs free energy
| sodium hydroxide | acetic acid | water | sodium acetate molecular free energy | -379.7 kJ/mol | -389.9 kJ/mol | -237.1 kJ/mol | -607.2 kJ/mol total free energy | -379.7 kJ/mol | -389.9 kJ/mol | -237.1 kJ/mol | -607.2 kJ/mol | G_initial = -769.6 kJ/mol | | G_final = -844.3 kJ/mol | ΔG_rxn^0 | -844.3 kJ/mol - -769.6 kJ/mol = -74.7 kJ/mol (exergonic) | | |
Chemical names and formulas
| sodium hydroxide | acetic acid | water | sodium acetate Hill formula | HNaO | C_2H_4O_2 | H_2O | C_2H_3NaO_2 name | sodium hydroxide | acetic acid | water | sodium acetate