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SO2 + O3 = O2 + SO3

Input interpretation

SO_2 sulfur dioxide + O_3 ozone ⟶ O_2 oxygen + SO_3 sulfur trioxide
SO_2 sulfur dioxide + O_3 ozone ⟶ O_2 oxygen + SO_3 sulfur trioxide

Balanced equation

Balance the chemical equation algebraically: SO_2 + O_3 ⟶ O_2 + SO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 SO_2 + c_2 O_3 ⟶ c_3 O_2 + c_4 SO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for O and S: O: | 2 c_1 + 3 c_2 = 2 c_3 + 3 c_4 S: | c_1 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_3 = (3 c_2)/2 - 1/2 c_4 = 1 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_2 = 1 and solve for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | SO_2 + O_3 ⟶ O_2 + SO_3
Balance the chemical equation algebraically: SO_2 + O_3 ⟶ O_2 + SO_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 SO_2 + c_2 O_3 ⟶ c_3 O_2 + c_4 SO_3 Set the number of atoms in the reactants equal to the number of atoms in the products for O and S: O: | 2 c_1 + 3 c_2 = 2 c_3 + 3 c_4 S: | c_1 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_3 = (3 c_2)/2 - 1/2 c_4 = 1 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_2 = 1 and solve for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | SO_2 + O_3 ⟶ O_2 + SO_3

Structures

 + ⟶ +
+ ⟶ +

Names

sulfur dioxide + ozone ⟶ oxygen + sulfur trioxide
sulfur dioxide + ozone ⟶ oxygen + sulfur trioxide

Reaction thermodynamics

Gibbs free energy

 | sulfur dioxide | ozone | oxygen | sulfur trioxide molecular free energy | -300.1 kJ/mol | 163.2 kJ/mol | 231.7 kJ/mol | -373.8 kJ/mol total free energy | -300.1 kJ/mol | 163.2 kJ/mol | 231.7 kJ/mol | -373.8 kJ/mol  | G_initial = -136.9 kJ/mol | | G_final = -142.1 kJ/mol |  ΔG_rxn^0 | -142.1 kJ/mol - -136.9 kJ/mol = -5.2 kJ/mol (exergonic) | | |
| sulfur dioxide | ozone | oxygen | sulfur trioxide molecular free energy | -300.1 kJ/mol | 163.2 kJ/mol | 231.7 kJ/mol | -373.8 kJ/mol total free energy | -300.1 kJ/mol | 163.2 kJ/mol | 231.7 kJ/mol | -373.8 kJ/mol | G_initial = -136.9 kJ/mol | | G_final = -142.1 kJ/mol | ΔG_rxn^0 | -142.1 kJ/mol - -136.9 kJ/mol = -5.2 kJ/mol (exergonic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: SO_2 + O_3 ⟶ O_2 + SO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: SO_2 + O_3 ⟶ O_2 + SO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_2 | 1 | -1 O_3 | 1 | -1 O_2 | 1 | 1 SO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression SO_2 | 1 | -1 | ([SO2])^(-1) O_3 | 1 | -1 | ([O3])^(-1) O_2 | 1 | 1 | [O2] SO_3 | 1 | 1 | [SO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([SO2])^(-1) ([O3])^(-1) [O2] [SO3] = ([O2] [SO3])/([SO2] [O3])
Construct the equilibrium constant, K, expression for: SO_2 + O_3 ⟶ O_2 + SO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: SO_2 + O_3 ⟶ O_2 + SO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_2 | 1 | -1 O_3 | 1 | -1 O_2 | 1 | 1 SO_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression SO_2 | 1 | -1 | ([SO2])^(-1) O_3 | 1 | -1 | ([O3])^(-1) O_2 | 1 | 1 | [O2] SO_3 | 1 | 1 | [SO3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([SO2])^(-1) ([O3])^(-1) [O2] [SO3] = ([O2] [SO3])/([SO2] [O3])

Rate of reaction

Construct the rate of reaction expression for: SO_2 + O_3 ⟶ O_2 + SO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: SO_2 + O_3 ⟶ O_2 + SO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_2 | 1 | -1 O_3 | 1 | -1 O_2 | 1 | 1 SO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term SO_2 | 1 | -1 | -(Δ[SO2])/(Δt) O_3 | 1 | -1 | -(Δ[O3])/(Δt) O_2 | 1 | 1 | (Δ[O2])/(Δt) SO_3 | 1 | 1 | (Δ[SO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[SO2])/(Δt) = -(Δ[O3])/(Δt) = (Δ[O2])/(Δt) = (Δ[SO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: SO_2 + O_3 ⟶ O_2 + SO_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: SO_2 + O_3 ⟶ O_2 + SO_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SO_2 | 1 | -1 O_3 | 1 | -1 O_2 | 1 | 1 SO_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term SO_2 | 1 | -1 | -(Δ[SO2])/(Δt) O_3 | 1 | -1 | -(Δ[O3])/(Δt) O_2 | 1 | 1 | (Δ[O2])/(Δt) SO_3 | 1 | 1 | (Δ[SO3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[SO2])/(Δt) = -(Δ[O3])/(Δt) = (Δ[O2])/(Δt) = (Δ[SO3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | sulfur dioxide | ozone | oxygen | sulfur trioxide formula | SO_2 | O_3 | O_2 | SO_3 Hill formula | O_2S | O_3 | O_2 | O_3S name | sulfur dioxide | ozone | oxygen | sulfur trioxide IUPAC name | sulfur dioxide | ozone | molecular oxygen | sulfur trioxide
| sulfur dioxide | ozone | oxygen | sulfur trioxide formula | SO_2 | O_3 | O_2 | SO_3 Hill formula | O_2S | O_3 | O_2 | O_3S name | sulfur dioxide | ozone | oxygen | sulfur trioxide IUPAC name | sulfur dioxide | ozone | molecular oxygen | sulfur trioxide

Substance properties

 | sulfur dioxide | ozone | oxygen | sulfur trioxide molar mass | 64.06 g/mol | 47.997 g/mol | 31.998 g/mol | 80.06 g/mol phase | gas (at STP) | gas (at STP) | gas (at STP) | liquid (at STP) melting point | -73 °C | -192.2 °C | -218 °C | 16.8 °C boiling point | -10 °C | -111.9 °C | -183 °C | 44.7 °C density | 0.002619 g/cm^3 (at 25 °C) | 0.001962 g/cm^3 (at 25 °C) | 0.001429 g/cm^3 (at 0 °C) | 1.97 g/cm^3 solubility in water | | | | reacts surface tension | 0.02859 N/m | | 0.01347 N/m |  dynamic viscosity | 1.282×10^-5 Pa s (at 25 °C) | | 2.055×10^-5 Pa s (at 25 °C) | 0.00159 Pa s (at 30 °C) odor | | | odorless |
| sulfur dioxide | ozone | oxygen | sulfur trioxide molar mass | 64.06 g/mol | 47.997 g/mol | 31.998 g/mol | 80.06 g/mol phase | gas (at STP) | gas (at STP) | gas (at STP) | liquid (at STP) melting point | -73 °C | -192.2 °C | -218 °C | 16.8 °C boiling point | -10 °C | -111.9 °C | -183 °C | 44.7 °C density | 0.002619 g/cm^3 (at 25 °C) | 0.001962 g/cm^3 (at 25 °C) | 0.001429 g/cm^3 (at 0 °C) | 1.97 g/cm^3 solubility in water | | | | reacts surface tension | 0.02859 N/m | | 0.01347 N/m | dynamic viscosity | 1.282×10^-5 Pa s (at 25 °C) | | 2.055×10^-5 Pa s (at 25 °C) | 0.00159 Pa s (at 30 °C) odor | | | odorless |

Units