Input interpretation
oxygen + N-hexane ⟶ water + carbon dioxide
Balanced equation
Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 = c_3 + 2 c_4 C: | 6 c_2 = c_4 H: | 14 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 19/2 c_2 = 1 c_3 = 7 c_4 = 6 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 19 c_2 = 2 c_3 = 14 c_4 = 12 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 19 + 2 ⟶ 14 + 12
Structures
+ ⟶ +
Names
oxygen + N-hexane ⟶ water + carbon dioxide
Chemical names and formulas
| oxygen | N-hexane | water | carbon dioxide Hill formula | O_2 | C_6H_14 | H_2O | CO_2 name | oxygen | N-hexane | water | carbon dioxide IUPAC name | molecular oxygen | hexane | water | carbon dioxide