HNO3 + ZnS = H2O + S + NO + Zn(NO3)2

nitric acid + zinc sulfide ⟶ water + mixed sulfur + nitric oxide + Zn(NO3)2

Balance the chemical equation algebraically: + ⟶ + + + Zn(NO3)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 Zn(NO3)2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, S and Zn: H: | c_1 = 2 c_3 N: | c_1 = c_5 + 2 c_6 O: | 3 c_1 = c_3 + c_5 + 6 c_6 S: | c_2 = c_4 Zn: | c_2 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 3/2 c_3 = 2 c_4 = 3/2 c_5 = 1 c_6 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 8 c_2 = 3 c_3 = 4 c_4 = 3 c_5 = 2 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 8 + 3 ⟶ 4 + 3 + 2 + 3 Zn(NO3)2

+ ⟶ + + + Zn(NO3)2

nitric acid + zinc sulfide ⟶ water + mixed sulfur + nitric oxide + Zn(NO3)2

| nitric acid | zinc sulfide | water | mixed sulfur | nitric oxide | Zn(NO3)2 formula | | | | | | Zn(NO3)2 Hill formula | HNO_3 | SZn | H_2O | S | NO | N2O6Zn name | nitric acid | zinc sulfide | water | mixed sulfur | nitric oxide | IUPAC name | nitric acid | thioxozinc | water | sulfur | nitric oxide |