Input interpretation
oxygen + N-propanol ⟶ water + carbon dioxide
Balanced equation
Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 + c_2 = c_3 + 2 c_4 C: | 3 c_2 = c_4 H: | 8 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 9/2 c_2 = 1 c_3 = 4 c_4 = 3 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 9 c_2 = 2 c_3 = 8 c_4 = 6 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 9 + 2 ⟶ 8 + 6
Structures
+ ⟶ +
Names
oxygen + N-propanol ⟶ water + carbon dioxide
Chemical names and formulas
| oxygen | N-propanol | water | carbon dioxide Hill formula | O_2 | C_3H_8O | H_2O | CO_2 name | oxygen | N-propanol | water | carbon dioxide IUPAC name | molecular oxygen | propan-1-ol | water | carbon dioxide