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NH3 + H2O2 + As2S3 = H2O + H3AsO4 + (NH3)2SO4

Input interpretation

NH_3 ammonia + H_2O_2 hydrogen peroxide + As_2S_3 arsenic(III) sulfide ⟶ H_2O water + H_3AsO_4 arsenic acid, solid + NH_2NH_2·H_2SO_4 hydrazine sulfate
NH_3 ammonia + H_2O_2 hydrogen peroxide + As_2S_3 arsenic(III) sulfide ⟶ H_2O water + H_3AsO_4 arsenic acid, solid + NH_2NH_2·H_2SO_4 hydrazine sulfate

Balanced equation

Balance the chemical equation algebraically: NH_3 + H_2O_2 + As_2S_3 ⟶ H_2O + H_3AsO_4 + NH_2NH_2·H_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NH_3 + c_2 H_2O_2 + c_3 As_2S_3 ⟶ c_4 H_2O + c_5 H_3AsO_4 + c_6 NH_2NH_2·H_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, As and S: H: | 3 c_1 + 2 c_2 = 2 c_4 + 3 c_5 + 6 c_6 N: | c_1 = 2 c_6 O: | 2 c_2 = c_4 + 4 c_5 + 4 c_6 As: | 2 c_3 = c_5 S: | 3 c_3 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 17 c_3 = 1 c_4 = 14 c_5 = 2 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 NH_3 + 17 H_2O_2 + As_2S_3 ⟶ 14 H_2O + 2 H_3AsO_4 + 3 NH_2NH_2·H_2SO_4
Balance the chemical equation algebraically: NH_3 + H_2O_2 + As_2S_3 ⟶ H_2O + H_3AsO_4 + NH_2NH_2·H_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NH_3 + c_2 H_2O_2 + c_3 As_2S_3 ⟶ c_4 H_2O + c_5 H_3AsO_4 + c_6 NH_2NH_2·H_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, As and S: H: | 3 c_1 + 2 c_2 = 2 c_4 + 3 c_5 + 6 c_6 N: | c_1 = 2 c_6 O: | 2 c_2 = c_4 + 4 c_5 + 4 c_6 As: | 2 c_3 = c_5 S: | 3 c_3 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 17 c_3 = 1 c_4 = 14 c_5 = 2 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 NH_3 + 17 H_2O_2 + As_2S_3 ⟶ 14 H_2O + 2 H_3AsO_4 + 3 NH_2NH_2·H_2SO_4

Structures

+ + ⟶ + +
+ + ⟶ + +

Names

ammonia + hydrogen peroxide + arsenic(III) sulfide ⟶ water + arsenic acid, solid + hydrazine sulfate
ammonia + hydrogen peroxide + arsenic(III) sulfide ⟶ water + arsenic acid, solid + hydrazine sulfate

Equilibrium constant

Construct the equilibrium constant, K, expression for: NH_3 + H_2O_2 + As_2S_3 ⟶ H_2O + H_3AsO_4 + NH_2NH_2·H_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 6 NH_3 + 17 H_2O_2 + As_2S_3 ⟶ 14 H_2O + 2 H_3AsO_4 + 3 NH_2NH_2·H_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_3 | 6 | -6 H_2O_2 | 17 | -17 As_2S_3 | 1 | -1 H_2O | 14 | 14 H_3AsO_4 | 2 | 2 NH_2NH_2·H_2SO_4 | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NH_3 | 6 | -6 | ([NH3])^(-6) H_2O_2 | 17 | -17 | ([H2O2])^(-17) As_2S_3 | 1 | -1 | ([As2S3])^(-1) H_2O | 14 | 14 | ([H2O])^14 H_3AsO_4 | 2 | 2 | ([H3AsO4])^2 NH_2NH_2·H_2SO_4 | 3 | 3 | ([NH2NH2·H2SO4])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NH3])^(-6) ([H2O2])^(-17) ([As2S3])^(-1) ([H2O])^14 ([H3AsO4])^2 ([NH2NH2·H2SO4])^3 = (([H2O])^14 ([H3AsO4])^2 ([NH2NH2·H2SO4])^3)/(([NH3])^6 ([H2O2])^17 [As2S3])
Construct the equilibrium constant, K, expression for: NH_3 + H_2O_2 + As_2S_3 ⟶ H_2O + H_3AsO_4 + NH_2NH_2·H_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 6 NH_3 + 17 H_2O_2 + As_2S_3 ⟶ 14 H_2O + 2 H_3AsO_4 + 3 NH_2NH_2·H_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_3 | 6 | -6 H_2O_2 | 17 | -17 As_2S_3 | 1 | -1 H_2O | 14 | 14 H_3AsO_4 | 2 | 2 NH_2NH_2·H_2SO_4 | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NH_3 | 6 | -6 | ([NH3])^(-6) H_2O_2 | 17 | -17 | ([H2O2])^(-17) As_2S_3 | 1 | -1 | ([As2S3])^(-1) H_2O | 14 | 14 | ([H2O])^14 H_3AsO_4 | 2 | 2 | ([H3AsO4])^2 NH_2NH_2·H_2SO_4 | 3 | 3 | ([NH2NH2·H2SO4])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NH3])^(-6) ([H2O2])^(-17) ([As2S3])^(-1) ([H2O])^14 ([H3AsO4])^2 ([NH2NH2·H2SO4])^3 = (([H2O])^14 ([H3AsO4])^2 ([NH2NH2·H2SO4])^3)/(([NH3])^6 ([H2O2])^17 [As2S3])

Rate of reaction

Construct the rate of reaction expression for: NH_3 + H_2O_2 + As_2S_3 ⟶ H_2O + H_3AsO_4 + NH_2NH_2·H_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 6 NH_3 + 17 H_2O_2 + As_2S_3 ⟶ 14 H_2O + 2 H_3AsO_4 + 3 NH_2NH_2·H_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_3 | 6 | -6 H_2O_2 | 17 | -17 As_2S_3 | 1 | -1 H_2O | 14 | 14 H_3AsO_4 | 2 | 2 NH_2NH_2·H_2SO_4 | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NH_3 | 6 | -6 | -1/6 (Δ[NH3])/(Δt) H_2O_2 | 17 | -17 | -1/17 (Δ[H2O2])/(Δt) As_2S_3 | 1 | -1 | -(Δ[As2S3])/(Δt) H_2O | 14 | 14 | 1/14 (Δ[H2O])/(Δt) H_3AsO_4 | 2 | 2 | 1/2 (Δ[H3AsO4])/(Δt) NH_2NH_2·H_2SO_4 | 3 | 3 | 1/3 (Δ[NH2NH2·H2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/6 (Δ[NH3])/(Δt) = -1/17 (Δ[H2O2])/(Δt) = -(Δ[As2S3])/(Δt) = 1/14 (Δ[H2O])/(Δt) = 1/2 (Δ[H3AsO4])/(Δt) = 1/3 (Δ[NH2NH2·H2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: NH_3 + H_2O_2 + As_2S_3 ⟶ H_2O + H_3AsO_4 + NH_2NH_2·H_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 6 NH_3 + 17 H_2O_2 + As_2S_3 ⟶ 14 H_2O + 2 H_3AsO_4 + 3 NH_2NH_2·H_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NH_3 | 6 | -6 H_2O_2 | 17 | -17 As_2S_3 | 1 | -1 H_2O | 14 | 14 H_3AsO_4 | 2 | 2 NH_2NH_2·H_2SO_4 | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NH_3 | 6 | -6 | -1/6 (Δ[NH3])/(Δt) H_2O_2 | 17 | -17 | -1/17 (Δ[H2O2])/(Δt) As_2S_3 | 1 | -1 | -(Δ[As2S3])/(Δt) H_2O | 14 | 14 | 1/14 (Δ[H2O])/(Δt) H_3AsO_4 | 2 | 2 | 1/2 (Δ[H3AsO4])/(Δt) NH_2NH_2·H_2SO_4 | 3 | 3 | 1/3 (Δ[NH2NH2·H2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/6 (Δ[NH3])/(Δt) = -1/17 (Δ[H2O2])/(Δt) = -(Δ[As2S3])/(Δt) = 1/14 (Δ[H2O])/(Δt) = 1/2 (Δ[H3AsO4])/(Δt) = 1/3 (Δ[NH2NH2·H2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| ammonia | hydrogen peroxide | arsenic(III) sulfide | water | arsenic acid, solid | hydrazine sulfate formula | NH_3 | H_2O_2 | As_2S_3 | H_2O | H_3AsO_4 | NH_2NH_2·H_2SO_4 Hill formula | H_3N | H_2O_2 | As_2S_3 | H_2O | AsH_3O_4 | H_6N_2O_4S name | ammonia | hydrogen peroxide | arsenic(III) sulfide | water | arsenic acid, solid | hydrazine sulfate IUPAC name | ammonia | hydrogen peroxide | | water | arsoric acid | hydrazine; sulfuric acid
| ammonia | hydrogen peroxide | arsenic(III) sulfide | water | arsenic acid, solid | hydrazine sulfate formula | NH_3 | H_2O_2 | As_2S_3 | H_2O | H_3AsO_4 | NH_2NH_2·H_2SO_4 Hill formula | H_3N | H_2O_2 | As_2S_3 | H_2O | AsH_3O_4 | H_6N_2O_4S name | ammonia | hydrogen peroxide | arsenic(III) sulfide | water | arsenic acid, solid | hydrazine sulfate IUPAC name | ammonia | hydrogen peroxide | | water | arsoric acid | hydrazine; sulfuric acid

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