Input interpretation
samarium(III) isopropoxide | molar mass
Result
![Find the molar mass, M, for samarium(III) isopropoxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Sm[OCH(CH_3)_2]_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 21 O (oxygen) | 3 Sm (samarium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 21 | 1.008 O (oxygen) | 3 | 15.999 Sm (samarium) | 1 | 150.36 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 21 | 1.008 | 21 × 1.008 = 21.168 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Sm (samarium) | 1 | 150.36 | 1 × 150.36 = 150.36 M = 108.099 g/mol + 21.168 g/mol + 47.997 g/mol + 150.36 g/mol = 327.62 g/mol](../image_source/c978ec9f0fbda88bf09107d82d385466.png)
Find the molar mass, M, for samarium(III) isopropoxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Sm[OCH(CH_3)_2]_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 21 O (oxygen) | 3 Sm (samarium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 21 | 1.008 O (oxygen) | 3 | 15.999 Sm (samarium) | 1 | 150.36 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 21 | 1.008 | 21 × 1.008 = 21.168 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Sm (samarium) | 1 | 150.36 | 1 × 150.36 = 150.36 M = 108.099 g/mol + 21.168 g/mol + 47.997 g/mol + 150.36 g/mol = 327.62 g/mol
Unit conversion
0.32762 kg/mol (kilograms per mole)
Comparisons
≈ 0.45 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5.4×10^-22 grams | 5.4×10^-25 kg (kilograms) | 328 u (unified atomic mass units) | 328 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 328