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C + Fe2O3 = CO + FeO

Input interpretation

C activated charcoal + Fe_2O_3 iron(III) oxide ⟶ CO carbon monoxide + FeO iron(II) oxide
C activated charcoal + Fe_2O_3 iron(III) oxide ⟶ CO carbon monoxide + FeO iron(II) oxide

Balanced equation

Balance the chemical equation algebraically: C + Fe_2O_3 ⟶ CO + FeO Add stoichiometric coefficients, c_i, to the reactants and products: c_1 C + c_2 Fe_2O_3 ⟶ c_3 CO + c_4 FeO Set the number of atoms in the reactants equal to the number of atoms in the products for C, Fe and O: C: | c_1 = c_3 Fe: | 2 c_2 = c_4 O: | 3 c_2 = c_3 + c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | C + Fe_2O_3 ⟶ CO + 2 FeO
Balance the chemical equation algebraically: C + Fe_2O_3 ⟶ CO + FeO Add stoichiometric coefficients, c_i, to the reactants and products: c_1 C + c_2 Fe_2O_3 ⟶ c_3 CO + c_4 FeO Set the number of atoms in the reactants equal to the number of atoms in the products for C, Fe and O: C: | c_1 = c_3 Fe: | 2 c_2 = c_4 O: | 3 c_2 = c_3 + c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | C + Fe_2O_3 ⟶ CO + 2 FeO

Structures

 + ⟶ +
+ ⟶ +

Names

activated charcoal + iron(III) oxide ⟶ carbon monoxide + iron(II) oxide
activated charcoal + iron(III) oxide ⟶ carbon monoxide + iron(II) oxide

Equilibrium constant

Construct the equilibrium constant, K, expression for: C + Fe_2O_3 ⟶ CO + FeO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: C + Fe_2O_3 ⟶ CO + 2 FeO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i C | 1 | -1 Fe_2O_3 | 1 | -1 CO | 1 | 1 FeO | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression C | 1 | -1 | ([C])^(-1) Fe_2O_3 | 1 | -1 | ([Fe2O3])^(-1) CO | 1 | 1 | [CO] FeO | 2 | 2 | ([FeO])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([C])^(-1) ([Fe2O3])^(-1) [CO] ([FeO])^2 = ([CO] ([FeO])^2)/([C] [Fe2O3])
Construct the equilibrium constant, K, expression for: C + Fe_2O_3 ⟶ CO + FeO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: C + Fe_2O_3 ⟶ CO + 2 FeO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i C | 1 | -1 Fe_2O_3 | 1 | -1 CO | 1 | 1 FeO | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression C | 1 | -1 | ([C])^(-1) Fe_2O_3 | 1 | -1 | ([Fe2O3])^(-1) CO | 1 | 1 | [CO] FeO | 2 | 2 | ([FeO])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([C])^(-1) ([Fe2O3])^(-1) [CO] ([FeO])^2 = ([CO] ([FeO])^2)/([C] [Fe2O3])

Rate of reaction

Construct the rate of reaction expression for: C + Fe_2O_3 ⟶ CO + FeO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: C + Fe_2O_3 ⟶ CO + 2 FeO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i C | 1 | -1 Fe_2O_3 | 1 | -1 CO | 1 | 1 FeO | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term C | 1 | -1 | -(Δ[C])/(Δt) Fe_2O_3 | 1 | -1 | -(Δ[Fe2O3])/(Δt) CO | 1 | 1 | (Δ[CO])/(Δt) FeO | 2 | 2 | 1/2 (Δ[FeO])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[C])/(Δt) = -(Δ[Fe2O3])/(Δt) = (Δ[CO])/(Δt) = 1/2 (Δ[FeO])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: C + Fe_2O_3 ⟶ CO + FeO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: C + Fe_2O_3 ⟶ CO + 2 FeO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i C | 1 | -1 Fe_2O_3 | 1 | -1 CO | 1 | 1 FeO | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term C | 1 | -1 | -(Δ[C])/(Δt) Fe_2O_3 | 1 | -1 | -(Δ[Fe2O3])/(Δt) CO | 1 | 1 | (Δ[CO])/(Δt) FeO | 2 | 2 | 1/2 (Δ[FeO])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[C])/(Δt) = -(Δ[Fe2O3])/(Δt) = (Δ[CO])/(Δt) = 1/2 (Δ[FeO])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | activated charcoal | iron(III) oxide | carbon monoxide | iron(II) oxide formula | C | Fe_2O_3 | CO | FeO name | activated charcoal | iron(III) oxide | carbon monoxide | iron(II) oxide IUPAC name | carbon | | carbon monoxide | oxoiron
| activated charcoal | iron(III) oxide | carbon monoxide | iron(II) oxide formula | C | Fe_2O_3 | CO | FeO name | activated charcoal | iron(III) oxide | carbon monoxide | iron(II) oxide IUPAC name | carbon | | carbon monoxide | oxoiron

Substance properties

 | activated charcoal | iron(III) oxide | carbon monoxide | iron(II) oxide molar mass | 12.011 g/mol | 159.69 g/mol | 28.01 g/mol | 71.844 g/mol phase | solid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 3550 °C | 1565 °C | -205 °C | 1360 °C boiling point | 4027 °C | | -191.5 °C |  density | 2.26 g/cm^3 | 5.26 g/cm^3 | 0.001145 g/cm^3 (at 25 °C) | 5.7 g/cm^3 solubility in water | insoluble | insoluble | | insoluble dynamic viscosity | | | 1.772×10^-5 Pa s (at 25 °C) |  odor | | odorless | odorless |
| activated charcoal | iron(III) oxide | carbon monoxide | iron(II) oxide molar mass | 12.011 g/mol | 159.69 g/mol | 28.01 g/mol | 71.844 g/mol phase | solid (at STP) | solid (at STP) | gas (at STP) | solid (at STP) melting point | 3550 °C | 1565 °C | -205 °C | 1360 °C boiling point | 4027 °C | | -191.5 °C | density | 2.26 g/cm^3 | 5.26 g/cm^3 | 0.001145 g/cm^3 (at 25 °C) | 5.7 g/cm^3 solubility in water | insoluble | insoluble | | insoluble dynamic viscosity | | | 1.772×10^-5 Pa s (at 25 °C) | odor | | odorless | odorless |

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