Input interpretation
pentaamminechloroiridium(III) chloride | molar mass
Result
![Find the molar mass, M, for pentaamminechloroiridium(III) chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: [Ir(NH_3)_5Cl]Cl_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 H (hydrogen) | 15 Ir (iridium) | 1 N (nitrogen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 H (hydrogen) | 15 | 1.008 Ir (iridium) | 1 | 192.217 N (nitrogen) | 5 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 Ir (iridium) | 1 | 192.217 | 1 × 192.217 = 192.217 N (nitrogen) | 5 | 14.007 | 5 × 14.007 = 70.035 M = 106.35 g/mol + 15.120 g/mol + 192.217 g/mol + 70.035 g/mol = 383.72 g/mol](../image_source/992e189be96306fa6dbf897a4cfbb678.png)
Find the molar mass, M, for pentaamminechloroiridium(III) chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: [Ir(NH_3)_5Cl]Cl_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 H (hydrogen) | 15 Ir (iridium) | 1 N (nitrogen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 H (hydrogen) | 15 | 1.008 Ir (iridium) | 1 | 192.217 N (nitrogen) | 5 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 Ir (iridium) | 1 | 192.217 | 1 × 192.217 = 192.217 N (nitrogen) | 5 | 14.007 | 5 × 14.007 = 70.035 M = 106.35 g/mol + 15.120 g/mol + 192.217 g/mol + 70.035 g/mol = 383.72 g/mol
Unit conversion
0.3837 kg/mol (kilograms per mole)
Comparisons
≈ 0.53 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 6.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 6.4×10^-22 grams | 6.4×10^-25 kg (kilograms) | 384 u (unified atomic mass units) | 384 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 384