Zn(NO3)2NO3 = O2 + NO2 + ZnO

Zn(NO3)2NO3 ⟶ O_2 oxygen + NO_2 nitrogen dioxide + ZnO zinc oxide

Balance the chemical equation algebraically: Zn(NO3)2NO3 ⟶ O_2 + NO_2 + ZnO Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Zn(NO3)2NO3 ⟶ c_2 O_2 + c_3 NO_2 + c_4 ZnO Set the number of atoms in the reactants equal to the number of atoms in the products for Zn, N and O: Zn: | c_1 = c_4 N: | 3 c_1 = c_3 O: | 9 c_1 = 2 c_2 + 2 c_3 + c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | Zn(NO3)2NO3 ⟶ O_2 + 3 NO_2 + ZnO

Zn(NO3)2NO3 ⟶ + +

Zn(NO3)2NO3 ⟶ oxygen + nitrogen dioxide + zinc oxide

Construct the equilibrium constant, K, expression for: Zn(NO3)2NO3 ⟶ O_2 + NO_2 + ZnO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: Zn(NO3)2NO3 ⟶ O_2 + 3 NO_2 + ZnO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Zn(NO3)2NO3 | 1 | -1 O_2 | 1 | 1 NO_2 | 3 | 3 ZnO | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Zn(NO3)2NO3 | 1 | -1 | ([Zn(NO3)2NO3])^(-1) O_2 | 1 | 1 | [O2] NO_2 | 3 | 3 | ([NO2])^3 ZnO | 1 | 1 | [ZnO] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Zn(NO3)2NO3])^(-1) [O2] ([NO2])^3 [ZnO] = ([O2] ([NO2])^3 [ZnO])/([Zn(NO3)2NO3])

Construct the rate of reaction expression for: Zn(NO3)2NO3 ⟶ O_2 + NO_2 + ZnO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: Zn(NO3)2NO3 ⟶ O_2 + 3 NO_2 + ZnO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Zn(NO3)2NO3 | 1 | -1 O_2 | 1 | 1 NO_2 | 3 | 3 ZnO | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Zn(NO3)2NO3 | 1 | -1 | -(Δ[Zn(NO3)2NO3])/(Δt) O_2 | 1 | 1 | (Δ[O2])/(Δt) NO_2 | 3 | 3 | 1/3 (Δ[NO2])/(Δt) ZnO | 1 | 1 | (Δ[ZnO])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[Zn(NO3)2NO3])/(Δt) = (Δ[O2])/(Δt) = 1/3 (Δ[NO2])/(Δt) = (Δ[ZnO])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| Zn(NO3)2NO3 | oxygen | nitrogen dioxide | zinc oxide formula | Zn(NO3)2NO3 | O_2 | NO_2 | ZnO Hill formula | N3O9Zn | O_2 | NO_2 | OZn name | | oxygen | nitrogen dioxide | zinc oxide IUPAC name | | molecular oxygen | Nitrogen dioxide | oxozinc

| Zn(NO3)2NO3 | oxygen | nitrogen dioxide | zinc oxide molar mass | 251.4 g/mol | 31.998 g/mol | 46.005 g/mol | 81.38 g/mol phase | | gas (at STP) | gas (at STP) | solid (at STP) melting point | | -218 °C | -11 °C | 1975 °C boiling point | | -183 °C | 21 °C | 2360 °C density | | 0.001429 g/cm^3 (at 0 °C) | 0.00188 g/cm^3 (at 25 °C) | 5.6 g/cm^3 solubility in water | | | reacts | surface tension | | 0.01347 N/m | | dynamic viscosity | | 2.055×10^-5 Pa s (at 25 °C) | 4.02×10^-4 Pa s (at 25 °C) | odor | | odorless | | odorless