Input interpretation
![5-chloro-1-methyl-1H-imidazole | molar mass](../image_source/70bb6f0aff5b99f9ecef8e93b21e2c51.png)
5-chloro-1-methyl-1H-imidazole | molar mass
Result
![Find the molar mass, M, for 5-chloro-1-methyl-1H-imidazole: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_4H_5ClN_2 Use the chemical formula, C_4H_5ClN_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 Cl (chlorine) | 1 H (hydrogen) | 5 N (nitrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 5 | 1.008 N (nitrogen) | 2 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 M = 48.044 g/mol + 35.45 g/mol + 5.040 g/mol + 28.014 g/mol = 116.55 g/mol](../image_source/32e7def716e36674f2fcb8179a36a961.png)
Find the molar mass, M, for 5-chloro-1-methyl-1H-imidazole: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_4H_5ClN_2 Use the chemical formula, C_4H_5ClN_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 Cl (chlorine) | 1 H (hydrogen) | 5 N (nitrogen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 5 | 1.008 N (nitrogen) | 2 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 M = 48.044 g/mol + 35.45 g/mol + 5.040 g/mol + 28.014 g/mol = 116.55 g/mol
Unit conversion
![0.1165 kg/mol (kilograms per mole)](../image_source/7f244b9d27c6e08086d99133595e66a7.png)
0.1165 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.16 ≈ 1/6 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/a9b1d293d4a03af4e2f86a883a3e1cb3.png)
≈ ( 0.16 ≈ 1/6 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.6 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/ca5246cd9a5d913b116a952d6e041dd0.png)
≈ 0.6 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/968c5642b8bd61be3ab5bc9d51bf1172.png)
≈ 2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.9×10^-22 grams | 1.9×10^-25 kg (kilograms) | 117 u (unified atomic mass units) | 117 Da (daltons)](../image_source/05e620d012bc6d5ac178fc96838a80e5.png)
Mass of a molecule m from m = M/N_A: | 1.9×10^-22 grams | 1.9×10^-25 kg (kilograms) | 117 u (unified atomic mass units) | 117 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 117](../image_source/51d46e7680edbab949df7a902afa3c2d.png)
Relative molecular mass M_r from M_r = M_u/M: | 117