Input interpretation
cadmium bis(dimethyldithiocarbamate) | molar mass
Result
Find the molar mass, M, for cadmium bis(dimethyldithiocarbamate): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_12CdN_2S_4 Use the chemical formula, C_6H_12CdN_2S_4, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 Cd (cadmium) | 1 H (hydrogen) | 12 N (nitrogen) | 2 S (sulfur) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 Cd (cadmium) | 1 | 112.414 H (hydrogen) | 12 | 1.008 N (nitrogen) | 2 | 14.007 S (sulfur) | 4 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 Cd (cadmium) | 1 | 112.414 | 1 × 112.414 = 112.414 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 S (sulfur) | 4 | 32.06 | 4 × 32.06 = 128.24 M = 72.066 g/mol + 112.414 g/mol + 12.096 g/mol + 28.014 g/mol + 128.24 g/mol = 352.83 g/mol
Unit conversion
0.3528 kg/mol (kilograms per mole)
Comparisons
≈ 0.49 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5.9×10^-22 grams | 5.9×10^-25 kg (kilograms) | 353 u (unified atomic mass units) | 353 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 353