Input interpretation
![manganese(II) nitrate | molar mass](../image_source/a14231e1aa391f8693d44244e4a9f685.png)
manganese(II) nitrate | molar mass
Result
![Find the molar mass, M, for manganese(II) nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Mn(NO_3)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Mn (manganese) | 1 N (nitrogen) | 2 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Mn (manganese) | 1 | 54.938044 N (nitrogen) | 2 | 14.007 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Mn (manganese) | 1 | 54.938044 | 1 × 54.938044 = 54.938044 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 54.938044 g/mol + 28.014 g/mol + 95.994 g/mol = 178.946 g/mol](../image_source/24810b36d768bfacc0cc8c56db66374c.png)
Find the molar mass, M, for manganese(II) nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Mn(NO_3)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Mn (manganese) | 1 N (nitrogen) | 2 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Mn (manganese) | 1 | 54.938044 N (nitrogen) | 2 | 14.007 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Mn (manganese) | 1 | 54.938044 | 1 × 54.938044 = 54.938044 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 54.938044 g/mol + 28.014 g/mol + 95.994 g/mol = 178.946 g/mol
Unit conversion
![0.17895 kg/mol (kilograms per mole)](../image_source/3eed8dc802758c94c70b208ddfec8143.png)
0.17895 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.25 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/a134d5b953e5ce2c125b127721e6c644.png)
≈ ( 0.25 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.92 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/3a25d6f97e51eab41c8ae28fb72a2602.png)
≈ 0.92 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/4872c2f545fd653cdf473c2b8839d64f.png)
≈ 3.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3×10^-22 grams | 3×10^-25 kg (kilograms) | 179 u (unified atomic mass units) | 179 Da (daltons)](../image_source/9efaeb8e46054c27223b077ce3461589.png)
Mass of a molecule m from m = M/N_A: | 3×10^-22 grams | 3×10^-25 kg (kilograms) | 179 u (unified atomic mass units) | 179 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 179](../image_source/f0d0cf6e8f9006ff55d928f5e83182e4.png)
Relative molecular mass M_r from M_r = M_u/M: | 179