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molar mass of amineptine

Input interpretation

amineptine | molar mass
amineptine | molar mass

Result

Find the molar mass, M, for amineptine: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_22H_28ClNO_2 Use the chemical formula, C_22H_28ClNO_2, to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 22  Cl (chlorine) | 1  H (hydrogen) | 28  N (nitrogen) | 1  O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 22 | 12.011  Cl (chlorine) | 1 | 35.45  H (hydrogen) | 28 | 1.008  N (nitrogen) | 1 | 14.007  O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 22 | 12.011 | 22 × 12.011 = 264.242  Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45  H (hydrogen) | 28 | 1.008 | 28 × 1.008 = 28.224  N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007  O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998  M = 264.242 g/mol + 35.45 g/mol + 28.224 g/mol + 14.007 g/mol + 31.998 g/mol = 373.92 g/mol
Find the molar mass, M, for amineptine: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_22H_28ClNO_2 Use the chemical formula, C_22H_28ClNO_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 22 Cl (chlorine) | 1 H (hydrogen) | 28 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 22 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 28 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 22 | 12.011 | 22 × 12.011 = 264.242 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 28 | 1.008 | 28 × 1.008 = 28.224 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 264.242 g/mol + 35.45 g/mol + 28.224 g/mol + 14.007 g/mol + 31.998 g/mol = 373.92 g/mol

Unit conversion

0.37392 kg/mol (kilograms per mole)
0.37392 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 6.2×10^-22 grams  | 6.2×10^-25 kg (kilograms)  | 374 u (unified atomic mass units)  | 374 Da (daltons)
Mass of a molecule m from m = M/N_A: | 6.2×10^-22 grams | 6.2×10^-25 kg (kilograms) | 374 u (unified atomic mass units) | 374 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 374
Relative molecular mass M_r from M_r = M_u/M: | 374