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molar mass of 4-ethynyl-α,α,α-trifluorotoluene

Input interpretation

4-ethynyl-α, α, α-trifluorotoluene | molar mass
4-ethynyl-α, α, α-trifluorotoluene | molar mass

Result

Find the molar mass, M, for 4-ethynyl-α, α, α-trifluorotoluene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: HC congruent CC_6H_4CF_3 Use the chemical formula, HC congruent CC_6H_4CF_3, to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 9  F (fluorine) | 3  H (hydrogen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 9 | 12.011  F (fluorine) | 3 | 18.998403163  H (hydrogen) | 5 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099  F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489  H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040  M = 108.099 g/mol + 56.995209489 g/mol + 5.040 g/mol = 170.134 g/mol
Find the molar mass, M, for 4-ethynyl-α, α, α-trifluorotoluene: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: HC congruent CC_6H_4CF_3 Use the chemical formula, HC congruent CC_6H_4CF_3, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 F (fluorine) | 3 H (hydrogen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 5 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 5 | 1.008 | 5 × 1.008 = 5.040 M = 108.099 g/mol + 56.995209489 g/mol + 5.040 g/mol = 170.134 g/mol

Unit conversion

0.17013 kg/mol (kilograms per mole)
0.17013 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.24 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.24 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.88 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.88 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 2.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 2.9 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 2.8×10^-22 grams  | 2.8×10^-25 kg (kilograms)  | 170 u (unified atomic mass units)  | 170 Da (daltons)
Mass of a molecule m from m = M/N_A: | 2.8×10^-22 grams | 2.8×10^-25 kg (kilograms) | 170 u (unified atomic mass units) | 170 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 170
Relative molecular mass M_r from M_r = M_u/M: | 170