Input interpretation
silver nitrate | molecular mass
Result
Find the molecular mass, m, for silver nitrate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: AgNO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ag (silver) | 1 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u Ag (silver) | 1 | 107.8682 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u Ag (silver) | 1 | 107.8682 | 1 × 107.8682 = 107.8682 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 m = 107.8682 u + 14.007 u + 47.997 u = 169.872 u
Unit conversions
169.87 Da (daltons)
0.16987 kDa (kilodaltons)
2.8208×10^-22 grams
2.8208×10^-25 kg (kilograms)
169.88 chemical atomic mass units (unit officially deprecated)
169.93 physical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
≈ ( 0.24 ≈ 1/4 ) × molecular mass of fullerene ( ≈ 721 u )
≈ 0.87 × molecular mass of caffeine ( ≈ 194 u )
≈ 2.9 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 170
Molar mass M from M = m_aN_A: | 170 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 170
Molar mass M from M = m_mN_A: | 170 g/mol (grams per mole)