H2O + HNO3 + As2O3 = H3AsO4 + N2O3

water + nitric acid + arsenic trioxide ⟶ arsenic acid, solid + nitrogen trioxide

Balance the chemical equation algebraically: + + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, N and As: H: | 2 c_1 + c_2 = 3 c_4 O: | c_1 + 3 c_2 + 3 c_3 = 4 c_4 + 3 c_5 N: | c_2 = 2 c_5 As: | 2 c_3 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 1 c_4 = 2 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 + 2 + ⟶ 2 +

+ + ⟶ +

water + nitric acid + arsenic trioxide ⟶ arsenic acid, solid + nitrogen trioxide

| water | nitric acid | arsenic trioxide | arsenic acid, solid | nitrogen trioxide Hill formula | H_2O | HNO_3 | As_2O_3 | AsH_3O_4 | N_2O_3 name | water | nitric acid | arsenic trioxide | arsenic acid, solid | nitrogen trioxide IUPAC name | water | nitric acid | 2, 4, 5-trioxa-1, 3-diarsabicyclo[1.1.1]pentane | arsoric acid | nitramide