H2SO4 + Li2SO3 + Li2Cr2O7 = H2O + Cr2(SO4)3 + Li2SO4

Input interpretation

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sulfuric acid + Li2SO3 + lithium dichromate ⟶ water + chromium sulfate + lithium sulfate

Balanced equation

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Balance the chemical equation algebraically: + Li2SO3 + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 Li2SO3 + c_3 ⟶ c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Li and Cr: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 3 c_2 + 7 c_3 = c_4 + 12 c_5 + 4 c_6 S: | c_1 + c_2 = 3 c_5 + c_6 Li: | 2 c_2 + 2 c_3 = 2 c_6 Cr: | 2 c_3 = 2 c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 3 c_3 = 1 c_4 = 4 c_5 = 1 c_6 = 4 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + 3 Li2SO3 + ⟶ 4 + + 4