Input interpretation
![2, 5-bis(trifluoromethyl)benzaldehyde | molar mass](../image_source/108de3da6e61b7f3a0ae427ae04ed375.png)
2, 5-bis(trifluoromethyl)benzaldehyde | molar mass
Result
![Find the molar mass, M, for 2, 5-bis(trifluoromethyl)benzaldehyde: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (CF_3)_2C_6H_3CHO Use the chemical formula, (CF_3)_2C_6H_3CHO, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 F (fluorine) | 6 H (hydrogen) | 4 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 F (fluorine) | 6 | 18.998403163 H (hydrogen) | 4 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 108.099 g/mol + 113.990418978 g/mol + 4.032 g/mol + 15.999 g/mol = 242.120 g/mol](../image_source/850d5d7d7efad5d9861559911427d8af.png)
Find the molar mass, M, for 2, 5-bis(trifluoromethyl)benzaldehyde: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (CF_3)_2C_6H_3CHO Use the chemical formula, (CF_3)_2C_6H_3CHO, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 F (fluorine) | 6 H (hydrogen) | 4 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 F (fluorine) | 6 | 18.998403163 H (hydrogen) | 4 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 F (fluorine) | 6 | 18.998403163 | 6 × 18.998403163 = 113.990418978 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 108.099 g/mol + 113.990418978 g/mol + 4.032 g/mol + 15.999 g/mol = 242.120 g/mol
Unit conversion
![0.24212 kg/mol (kilograms per mole)](../image_source/7271c147a31f834d93a228e99328cf61.png)
0.24212 kg/mol (kilograms per mole)
Comparisons
![≈ 0.34 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/06d0fd6b2669eee9109f56f5895e2c6e.png)
≈ 0.34 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/b80d014f04316bc3155429b6607fc20f.png)
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/71b6d5308ac8f147f2d82fff1125521e.png)
≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4×10^-22 grams | 4×10^-25 kg (kilograms) | 242 u (unified atomic mass units) | 242 Da (daltons)](../image_source/4cf02304c1f9a165f149e8c8549a7fdd.png)
Mass of a molecule m from m = M/N_A: | 4×10^-22 grams | 4×10^-25 kg (kilograms) | 242 u (unified atomic mass units) | 242 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 242](../image_source/9270427429e97a273cd8876b1a80ce76.png)
Relative molecular mass M_r from M_r = M_u/M: | 242