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H2O2 + Na2S = H2O + Na2SO4

Input interpretation

H_2O_2 hydrogen peroxide + Na_2S sodium sulfide ⟶ H_2O water + Na_2SO_4 sodium sulfate
H_2O_2 hydrogen peroxide + Na_2S sodium sulfide ⟶ H_2O water + Na_2SO_4 sodium sulfate

Balanced equation

Balance the chemical equation algebraically: H_2O_2 + Na_2S ⟶ H_2O + Na_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O_2 + c_2 Na_2S ⟶ c_3 H_2O + c_4 Na_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Na and S: H: | 2 c_1 = 2 c_3 O: | 2 c_1 = c_3 + 4 c_4 Na: | 2 c_2 = 2 c_4 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 4 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 4 H_2O_2 + Na_2S ⟶ 4 H_2O + Na_2SO_4
Balance the chemical equation algebraically: H_2O_2 + Na_2S ⟶ H_2O + Na_2SO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O_2 + c_2 Na_2S ⟶ c_3 H_2O + c_4 Na_2SO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, Na and S: H: | 2 c_1 = 2 c_3 O: | 2 c_1 = c_3 + 4 c_4 Na: | 2 c_2 = 2 c_4 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 1 c_3 = 4 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 H_2O_2 + Na_2S ⟶ 4 H_2O + Na_2SO_4

Structures

 + ⟶ +
+ ⟶ +

Names

hydrogen peroxide + sodium sulfide ⟶ water + sodium sulfate
hydrogen peroxide + sodium sulfide ⟶ water + sodium sulfate

Reaction thermodynamics

Gibbs free energy

 | hydrogen peroxide | sodium sulfide | water | sodium sulfate molecular free energy | -120.4 kJ/mol | -349.8 kJ/mol | -237.1 kJ/mol | -1270 kJ/mol total free energy | -481.6 kJ/mol | -349.8 kJ/mol | -948.4 kJ/mol | -1270 kJ/mol  | G_initial = -831.4 kJ/mol | | G_final = -2219 kJ/mol |  ΔG_rxn^0 | -2219 kJ/mol - -831.4 kJ/mol = -1387 kJ/mol (exergonic) | | |
| hydrogen peroxide | sodium sulfide | water | sodium sulfate molecular free energy | -120.4 kJ/mol | -349.8 kJ/mol | -237.1 kJ/mol | -1270 kJ/mol total free energy | -481.6 kJ/mol | -349.8 kJ/mol | -948.4 kJ/mol | -1270 kJ/mol | G_initial = -831.4 kJ/mol | | G_final = -2219 kJ/mol | ΔG_rxn^0 | -2219 kJ/mol - -831.4 kJ/mol = -1387 kJ/mol (exergonic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2O_2 + Na_2S ⟶ H_2O + Na_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 4 H_2O_2 + Na_2S ⟶ 4 H_2O + Na_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O_2 | 4 | -4 Na_2S | 1 | -1 H_2O | 4 | 4 Na_2SO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O_2 | 4 | -4 | ([H2O2])^(-4) Na_2S | 1 | -1 | ([Na2S])^(-1) H_2O | 4 | 4 | ([H2O])^4 Na_2SO_4 | 1 | 1 | [Na2SO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([H2O2])^(-4) ([Na2S])^(-1) ([H2O])^4 [Na2SO4] = (([H2O])^4 [Na2SO4])/(([H2O2])^4 [Na2S])
Construct the equilibrium constant, K, expression for: H_2O_2 + Na_2S ⟶ H_2O + Na_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 4 H_2O_2 + Na_2S ⟶ 4 H_2O + Na_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O_2 | 4 | -4 Na_2S | 1 | -1 H_2O | 4 | 4 Na_2SO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O_2 | 4 | -4 | ([H2O2])^(-4) Na_2S | 1 | -1 | ([Na2S])^(-1) H_2O | 4 | 4 | ([H2O])^4 Na_2SO_4 | 1 | 1 | [Na2SO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O2])^(-4) ([Na2S])^(-1) ([H2O])^4 [Na2SO4] = (([H2O])^4 [Na2SO4])/(([H2O2])^4 [Na2S])

Rate of reaction

Construct the rate of reaction expression for: H_2O_2 + Na_2S ⟶ H_2O + Na_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 4 H_2O_2 + Na_2S ⟶ 4 H_2O + Na_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O_2 | 4 | -4 Na_2S | 1 | -1 H_2O | 4 | 4 Na_2SO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O_2 | 4 | -4 | -1/4 (Δ[H2O2])/(Δt) Na_2S | 1 | -1 | -(Δ[Na2S])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) Na_2SO_4 | 1 | 1 | (Δ[Na2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/4 (Δ[H2O2])/(Δt) = -(Δ[Na2S])/(Δt) = 1/4 (Δ[H2O])/(Δt) = (Δ[Na2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2O_2 + Na_2S ⟶ H_2O + Na_2SO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 4 H_2O_2 + Na_2S ⟶ 4 H_2O + Na_2SO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O_2 | 4 | -4 Na_2S | 1 | -1 H_2O | 4 | 4 Na_2SO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O_2 | 4 | -4 | -1/4 (Δ[H2O2])/(Δt) Na_2S | 1 | -1 | -(Δ[Na2S])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) Na_2SO_4 | 1 | 1 | (Δ[Na2SO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/4 (Δ[H2O2])/(Δt) = -(Δ[Na2S])/(Δt) = 1/4 (Δ[H2O])/(Δt) = (Δ[Na2SO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | hydrogen peroxide | sodium sulfide | water | sodium sulfate formula | H_2O_2 | Na_2S | H_2O | Na_2SO_4 Hill formula | H_2O_2 | Na_2S_1 | H_2O | Na_2O_4S name | hydrogen peroxide | sodium sulfide | water | sodium sulfate IUPAC name | hydrogen peroxide | | water | disodium sulfate
| hydrogen peroxide | sodium sulfide | water | sodium sulfate formula | H_2O_2 | Na_2S | H_2O | Na_2SO_4 Hill formula | H_2O_2 | Na_2S_1 | H_2O | Na_2O_4S name | hydrogen peroxide | sodium sulfide | water | sodium sulfate IUPAC name | hydrogen peroxide | | water | disodium sulfate

Substance properties

 | hydrogen peroxide | sodium sulfide | water | sodium sulfate molar mass | 34.014 g/mol | 78.04 g/mol | 18.015 g/mol | 142.04 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | -0.43 °C | 1172 °C | 0 °C | 884 °C boiling point | 150.2 °C | | 99.9839 °C | 1429 °C density | 1.44 g/cm^3 | 1.856 g/cm^3 | 1 g/cm^3 | 2.68 g/cm^3 solubility in water | miscible | | | soluble surface tension | 0.0804 N/m | | 0.0728 N/m |  dynamic viscosity | 0.001249 Pa s (at 20 °C) | | 8.9×10^-4 Pa s (at 25 °C) |  odor | | | odorless |
| hydrogen peroxide | sodium sulfide | water | sodium sulfate molar mass | 34.014 g/mol | 78.04 g/mol | 18.015 g/mol | 142.04 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | -0.43 °C | 1172 °C | 0 °C | 884 °C boiling point | 150.2 °C | | 99.9839 °C | 1429 °C density | 1.44 g/cm^3 | 1.856 g/cm^3 | 1 g/cm^3 | 2.68 g/cm^3 solubility in water | miscible | | | soluble surface tension | 0.0804 N/m | | 0.0728 N/m | dynamic viscosity | 0.001249 Pa s (at 20 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units