H2O + La2O3 = La(OH)3

H_2O water + La_2O_3 lanthanum oxide ⟶ La(OH)_3 lanthanum hydroxide

Balance the chemical equation algebraically: H_2O + La_2O_3 ⟶ La(OH)_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 La_2O_3 ⟶ c_3 La(OH)_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O and La: H: | 2 c_1 = 3 c_3 O: | c_1 + 3 c_2 = 3 c_3 La: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 H_2O + La_2O_3 ⟶ 2 La(OH)_3

+ ⟶

water + lanthanum oxide ⟶ lanthanum hydroxide

Construct the equilibrium constant, K, expression for: H_2O + La_2O_3 ⟶ La(OH)_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 H_2O + La_2O_3 ⟶ 2 La(OH)_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 3 | -3 La_2O_3 | 1 | -1 La(OH)_3 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 3 | -3 | ([H2O])^(-3) La_2O_3 | 1 | -1 | ([La2O3])^(-1) La(OH)_3 | 2 | 2 | ([La(OH)3])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-3) ([La2O3])^(-1) ([La(OH)3])^2 = ([La(OH)3])^2/(([H2O])^3 [La2O3])

Construct the rate of reaction expression for: H_2O + La_2O_3 ⟶ La(OH)_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 H_2O + La_2O_3 ⟶ 2 La(OH)_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 3 | -3 La_2O_3 | 1 | -1 La(OH)_3 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 3 | -3 | -1/3 (Δ[H2O])/(Δt) La_2O_3 | 1 | -1 | -(Δ[La2O3])/(Δt) La(OH)_3 | 2 | 2 | 1/2 (Δ[La(OH)3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[H2O])/(Δt) = -(Δ[La2O3])/(Δt) = 1/2 (Δ[La(OH)3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| water | lanthanum oxide | lanthanum hydroxide formula | H_2O | La_2O_3 | La(OH)_3 Hill formula | H_2O | La_2O_3 | H_3LaO_3 name | water | lanthanum oxide | lanthanum hydroxide

| water | lanthanum oxide | lanthanum hydroxide molar mass | 18.015 g/mol | 325.808 g/mol | 189.93 g/mol phase | liquid (at STP) | solid (at STP) | melting point | 0 °C | 2315 °C | boiling point | 99.9839 °C | 4200 °C | density | 1 g/cm^3 | 6.51 g/cm^3 | 4.28 g/cm^3 solubility in water | | decomposes | insoluble surface tension | 0.0728 N/m | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | odor | odorless | |