Input interpretation
![cadmium selenate dihydrate | molar mass](../image_source/7088edb8a2a12eb3b01d5f6d7ca81a67.png)
cadmium selenate dihydrate | molar mass
Result
![Find the molar mass, M, for cadmium selenate dihydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CdSeO_4·2H_2O Use the chemical formula, CdSeO_4·2H_2O, to count the number of atoms, N_i, for each element: | N_i Cd (cadmium) | 1 H (hydrogen) | 4 O (oxygen) | 6 Se (selenium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cd (cadmium) | 1 | 112.414 H (hydrogen) | 4 | 1.008 O (oxygen) | 6 | 15.999 Se (selenium) | 1 | 78.971 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cd (cadmium) | 1 | 112.414 | 1 × 112.414 = 112.414 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 Se (selenium) | 1 | 78.971 | 1 × 78.971 = 78.971 M = 112.414 g/mol + 4.032 g/mol + 95.994 g/mol + 78.971 g/mol = 291.411 g/mol](../image_source/ebfa3484e12b6c20c49a85d72b728d3e.png)
Find the molar mass, M, for cadmium selenate dihydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CdSeO_4·2H_2O Use the chemical formula, CdSeO_4·2H_2O, to count the number of atoms, N_i, for each element: | N_i Cd (cadmium) | 1 H (hydrogen) | 4 O (oxygen) | 6 Se (selenium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cd (cadmium) | 1 | 112.414 H (hydrogen) | 4 | 1.008 O (oxygen) | 6 | 15.999 Se (selenium) | 1 | 78.971 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cd (cadmium) | 1 | 112.414 | 1 × 112.414 = 112.414 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 Se (selenium) | 1 | 78.971 | 1 × 78.971 = 78.971 M = 112.414 g/mol + 4.032 g/mol + 95.994 g/mol + 78.971 g/mol = 291.411 g/mol
Unit conversion
![0.29141 kg/mol (kilograms per mole)](../image_source/9a8abfffe2fb249c21cfe22db87b7276.png)
0.29141 kg/mol (kilograms per mole)
Comparisons
![≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/f0c2955aac61db3b4a19172118e53115.png)
≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/6d2612c0126367dc20333b84e38ccdd0.png)
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/af28dfb281b3536bb072fcdda2a928cf.png)
≈ 5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 291 u (unified atomic mass units) | 291 Da (daltons)](../image_source/db78ef1585c4d48b109dee5aa7197887.png)
Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 291 u (unified atomic mass units) | 291 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 291](../image_source/9548fc3d0ede9275ea678d0d45a54185.png)
Relative molecular mass M_r from M_r = M_u/M: | 291