Input interpretation
deuterium bromide
Chemical names and formulas
formula | DBr·D_2O Hill formula | BrD name | deuterium bromide mass fractions | Br (bromine) 0.975% | H (hydrogen) 0.0246%
Lewis structure
Draw the Lewis structure of deuterium bromide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the bromine (n_Br, val = 7) and hydrogen (n_H, val = 1) atoms: n_Br, val + n_H, val = 8 Calculate the number of electrons needed to completely fill the valence shells for bromine (n_Br, full = 8) and hydrogen (n_H, full = 2): n_Br, full + n_H, full = 10 Subtracting these two numbers shows that 10 - 8 = 2 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There is 1 bond and hence 2 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 8 - 2 = 6 electrons left to draw: Answer: | |
Basic properties
molar mass | 81.918 g/mol phase | liquid (at STP) boiling point | 126 °C density | 1.537 g/cm^3
Units
Liquid properties (at STP)
density | 1.537 g/cm^3
Units
Non-standard atom properties
H-2 | 1
Chemical identifiers
CAS number | 13536-59-9 PubChem CID number | 518779 PubChem SID number | 24850595 SMILES identifier | Br InChI identifier | InChI=1/BrH/h1H/i/hD/f/i1D MDL number | MFCD00044232