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O2 + C4H8O = H2O + CO2

Input interpretation

O_2 oxygen + C_4H_8O tetrahydrofuran ⟶ H_2O water + CO_2 carbon dioxide
O_2 oxygen + C_4H_8O tetrahydrofuran ⟶ H_2O water + CO_2 carbon dioxide

Balanced equation

Balance the chemical equation algebraically: O_2 + C_4H_8O ⟶ H_2O + CO_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 O_2 + c_2 C_4H_8O ⟶ c_3 H_2O + c_4 CO_2 Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 + c_2 = c_3 + 2 c_4 C: | 4 c_2 = c_4 H: | 8 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 11/2 c_2 = 1 c_3 = 4 c_4 = 4 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 11 c_2 = 2 c_3 = 8 c_4 = 8 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 11 O_2 + 2 C_4H_8O ⟶ 8 H_2O + 8 CO_2
Balance the chemical equation algebraically: O_2 + C_4H_8O ⟶ H_2O + CO_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 O_2 + c_2 C_4H_8O ⟶ c_3 H_2O + c_4 CO_2 Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 + c_2 = c_3 + 2 c_4 C: | 4 c_2 = c_4 H: | 8 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 11/2 c_2 = 1 c_3 = 4 c_4 = 4 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 11 c_2 = 2 c_3 = 8 c_4 = 8 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 11 O_2 + 2 C_4H_8O ⟶ 8 H_2O + 8 CO_2

Structures

 + ⟶ +
+ ⟶ +

Names

oxygen + tetrahydrofuran ⟶ water + carbon dioxide
oxygen + tetrahydrofuran ⟶ water + carbon dioxide

Equilibrium constant

Construct the equilibrium constant, K, expression for: O_2 + C_4H_8O ⟶ H_2O + CO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 11 O_2 + 2 C_4H_8O ⟶ 8 H_2O + 8 CO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 11 | -11 C_4H_8O | 2 | -2 H_2O | 8 | 8 CO_2 | 8 | 8 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression O_2 | 11 | -11 | ([O2])^(-11) C_4H_8O | 2 | -2 | ([C4H8O])^(-2) H_2O | 8 | 8 | ([H2O])^8 CO_2 | 8 | 8 | ([CO2])^8 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([O2])^(-11) ([C4H8O])^(-2) ([H2O])^8 ([CO2])^8 = (([H2O])^8 ([CO2])^8)/(([O2])^11 ([C4H8O])^2)
Construct the equilibrium constant, K, expression for: O_2 + C_4H_8O ⟶ H_2O + CO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 11 O_2 + 2 C_4H_8O ⟶ 8 H_2O + 8 CO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 11 | -11 C_4H_8O | 2 | -2 H_2O | 8 | 8 CO_2 | 8 | 8 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression O_2 | 11 | -11 | ([O2])^(-11) C_4H_8O | 2 | -2 | ([C4H8O])^(-2) H_2O | 8 | 8 | ([H2O])^8 CO_2 | 8 | 8 | ([CO2])^8 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([O2])^(-11) ([C4H8O])^(-2) ([H2O])^8 ([CO2])^8 = (([H2O])^8 ([CO2])^8)/(([O2])^11 ([C4H8O])^2)

Rate of reaction

Construct the rate of reaction expression for: O_2 + C_4H_8O ⟶ H_2O + CO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 11 O_2 + 2 C_4H_8O ⟶ 8 H_2O + 8 CO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 11 | -11 C_4H_8O | 2 | -2 H_2O | 8 | 8 CO_2 | 8 | 8 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term O_2 | 11 | -11 | -1/11 (Δ[O2])/(Δt) C_4H_8O | 2 | -2 | -1/2 (Δ[C4H8O])/(Δt) H_2O | 8 | 8 | 1/8 (Δ[H2O])/(Δt) CO_2 | 8 | 8 | 1/8 (Δ[CO2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/11 (Δ[O2])/(Δt) = -1/2 (Δ[C4H8O])/(Δt) = 1/8 (Δ[H2O])/(Δt) = 1/8 (Δ[CO2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: O_2 + C_4H_8O ⟶ H_2O + CO_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 11 O_2 + 2 C_4H_8O ⟶ 8 H_2O + 8 CO_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 11 | -11 C_4H_8O | 2 | -2 H_2O | 8 | 8 CO_2 | 8 | 8 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term O_2 | 11 | -11 | -1/11 (Δ[O2])/(Δt) C_4H_8O | 2 | -2 | -1/2 (Δ[C4H8O])/(Δt) H_2O | 8 | 8 | 1/8 (Δ[H2O])/(Δt) CO_2 | 8 | 8 | 1/8 (Δ[CO2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/11 (Δ[O2])/(Δt) = -1/2 (Δ[C4H8O])/(Δt) = 1/8 (Δ[H2O])/(Δt) = 1/8 (Δ[CO2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | oxygen | tetrahydrofuran | water | carbon dioxide formula | O_2 | C_4H_8O | H_2O | CO_2 name | oxygen | tetrahydrofuran | water | carbon dioxide IUPAC name | molecular oxygen | tetrahydrofuran | water | carbon dioxide
| oxygen | tetrahydrofuran | water | carbon dioxide formula | O_2 | C_4H_8O | H_2O | CO_2 name | oxygen | tetrahydrofuran | water | carbon dioxide IUPAC name | molecular oxygen | tetrahydrofuran | water | carbon dioxide