Input interpretation
![H_2SO_4 sulfuric acid + KI potassium iodide + NaOCl sodium hypochlorite ⟶ H_2O water + K_2SO_4 potassium sulfate + I_2 iodine + NaCl sodium chloride](../image_source/3f924c72f33dac8ea8033dd7023bd051.png)
H_2SO_4 sulfuric acid + KI potassium iodide + NaOCl sodium hypochlorite ⟶ H_2O water + K_2SO_4 potassium sulfate + I_2 iodine + NaCl sodium chloride
Balanced equation
![Balance the chemical equation algebraically: H_2SO_4 + KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 KI + c_3 NaOCl ⟶ c_4 H_2O + c_5 K_2SO_4 + c_6 I_2 + c_7 NaCl Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, I, K, Cl and Na: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + c_3 = c_4 + 4 c_5 S: | c_1 = c_5 I: | c_2 = 2 c_6 K: | c_2 = 2 c_5 Cl: | c_3 = c_7 Na: | c_3 = c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 1 c_4 = 1 c_5 = 1 c_6 = 1 c_7 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2SO_4 + 2 KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl](../image_source/275010e6f662439b0104ce3a6932012b.png)
Balance the chemical equation algebraically: H_2SO_4 + KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 KI + c_3 NaOCl ⟶ c_4 H_2O + c_5 K_2SO_4 + c_6 I_2 + c_7 NaCl Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, I, K, Cl and Na: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + c_3 = c_4 + 4 c_5 S: | c_1 = c_5 I: | c_2 = 2 c_6 K: | c_2 = 2 c_5 Cl: | c_3 = c_7 Na: | c_3 = c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 1 c_4 = 1 c_5 = 1 c_6 = 1 c_7 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2SO_4 + 2 KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl
Structures
![+ + ⟶ + + +](../image_source/e3832e7cfc098fec9fafaf48a91c8fb4.png)
+ + ⟶ + + +
Names
![sulfuric acid + potassium iodide + sodium hypochlorite ⟶ water + potassium sulfate + iodine + sodium chloride](../image_source/3f8f2a10f247333c0eff1beaf9f82cdf.png)
sulfuric acid + potassium iodide + sodium hypochlorite ⟶ water + potassium sulfate + iodine + sodium chloride
Equilibrium constant
![Construct the equilibrium constant, K, expression for: H_2SO_4 + KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2SO_4 + 2 KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 KI | 2 | -2 NaOCl | 1 | -1 H_2O | 1 | 1 K_2SO_4 | 1 | 1 I_2 | 1 | 1 NaCl | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 1 | -1 | ([H2SO4])^(-1) KI | 2 | -2 | ([KI])^(-2) NaOCl | 1 | -1 | ([NaOCl])^(-1) H_2O | 1 | 1 | [H2O] K_2SO_4 | 1 | 1 | [K2SO4] I_2 | 1 | 1 | [I2] NaCl | 1 | 1 | [NaCl] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-1) ([KI])^(-2) ([NaOCl])^(-1) [H2O] [K2SO4] [I2] [NaCl] = ([H2O] [K2SO4] [I2] [NaCl])/([H2SO4] ([KI])^2 [NaOCl])](../image_source/09edc88ccc16bc0830129aa9e9be53df.png)
Construct the equilibrium constant, K, expression for: H_2SO_4 + KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2SO_4 + 2 KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 KI | 2 | -2 NaOCl | 1 | -1 H_2O | 1 | 1 K_2SO_4 | 1 | 1 I_2 | 1 | 1 NaCl | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 1 | -1 | ([H2SO4])^(-1) KI | 2 | -2 | ([KI])^(-2) NaOCl | 1 | -1 | ([NaOCl])^(-1) H_2O | 1 | 1 | [H2O] K_2SO_4 | 1 | 1 | [K2SO4] I_2 | 1 | 1 | [I2] NaCl | 1 | 1 | [NaCl] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-1) ([KI])^(-2) ([NaOCl])^(-1) [H2O] [K2SO4] [I2] [NaCl] = ([H2O] [K2SO4] [I2] [NaCl])/([H2SO4] ([KI])^2 [NaOCl])
Rate of reaction
![Construct the rate of reaction expression for: H_2SO_4 + KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2SO_4 + 2 KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 KI | 2 | -2 NaOCl | 1 | -1 H_2O | 1 | 1 K_2SO_4 | 1 | 1 I_2 | 1 | 1 NaCl | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 1 | -1 | -(Δ[H2SO4])/(Δt) KI | 2 | -2 | -1/2 (Δ[KI])/(Δt) NaOCl | 1 | -1 | -(Δ[NaOCl])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) K_2SO_4 | 1 | 1 | (Δ[K2SO4])/(Δt) I_2 | 1 | 1 | (Δ[I2])/(Δt) NaCl | 1 | 1 | (Δ[NaCl])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2SO4])/(Δt) = -1/2 (Δ[KI])/(Δt) = -(Δ[NaOCl])/(Δt) = (Δ[H2O])/(Δt) = (Δ[K2SO4])/(Δt) = (Δ[I2])/(Δt) = (Δ[NaCl])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/b954a42e4deca4fe179a531843d80082.png)
Construct the rate of reaction expression for: H_2SO_4 + KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2SO_4 + 2 KI + NaOCl ⟶ H_2O + K_2SO_4 + I_2 + NaCl Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 1 | -1 KI | 2 | -2 NaOCl | 1 | -1 H_2O | 1 | 1 K_2SO_4 | 1 | 1 I_2 | 1 | 1 NaCl | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 1 | -1 | -(Δ[H2SO4])/(Δt) KI | 2 | -2 | -1/2 (Δ[KI])/(Δt) NaOCl | 1 | -1 | -(Δ[NaOCl])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) K_2SO_4 | 1 | 1 | (Δ[K2SO4])/(Δt) I_2 | 1 | 1 | (Δ[I2])/(Δt) NaCl | 1 | 1 | (Δ[NaCl])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2SO4])/(Δt) = -1/2 (Δ[KI])/(Δt) = -(Δ[NaOCl])/(Δt) = (Δ[H2O])/(Δt) = (Δ[K2SO4])/(Δt) = (Δ[I2])/(Δt) = (Δ[NaCl])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| sulfuric acid | potassium iodide | sodium hypochlorite | water | potassium sulfate | iodine | sodium chloride formula | H_2SO_4 | KI | NaOCl | H_2O | K_2SO_4 | I_2 | NaCl Hill formula | H_2O_4S | IK | ClNaO | H_2O | K_2O_4S | I_2 | ClNa name | sulfuric acid | potassium iodide | sodium hypochlorite | water | potassium sulfate | iodine | sodium chloride IUPAC name | sulfuric acid | potassium iodide | sodium hypochlorite | water | dipotassium sulfate | molecular iodine | sodium chloride](../image_source/a5ba800cc0e09d25c061dda160eeb9ce.png)
| sulfuric acid | potassium iodide | sodium hypochlorite | water | potassium sulfate | iodine | sodium chloride formula | H_2SO_4 | KI | NaOCl | H_2O | K_2SO_4 | I_2 | NaCl Hill formula | H_2O_4S | IK | ClNaO | H_2O | K_2O_4S | I_2 | ClNa name | sulfuric acid | potassium iodide | sodium hypochlorite | water | potassium sulfate | iodine | sodium chloride IUPAC name | sulfuric acid | potassium iodide | sodium hypochlorite | water | dipotassium sulfate | molecular iodine | sodium chloride