Input interpretation
![N-methylolacrylamide | molar mass](../image_source/40cc81efef272a48ffc392775b362437.png)
N-methylolacrylamide | molar mass
Result
![Find the molar mass, M, for N-methylolacrylamide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_2=CHCONHCH_2OH Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 H (hydrogen) | 7 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 H (hydrogen) | 7 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 48.044 g/mol + 7.056 g/mol + 14.007 g/mol + 31.998 g/mol = 101.105 g/mol](../image_source/9a45e227813aac43e9c8b707833fd4e5.png)
Find the molar mass, M, for N-methylolacrylamide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_2=CHCONHCH_2OH Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 H (hydrogen) | 7 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 H (hydrogen) | 7 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 48.044 g/mol + 7.056 g/mol + 14.007 g/mol + 31.998 g/mol = 101.105 g/mol
Unit conversion
![0.1011 kg/mol (kilograms per mole)](../image_source/e47c6c8248f3db50a65523c72de337b3.png)
0.1011 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/ed76ce3bf5b906d6bf6c1ff859dd3cab.png)
≈ ( 0.14 ≈ 1/7 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.52 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/62589fedceafaf889505f049fc926917.png)
≈ 0.52 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/83563ea629d1381a1365c7a37dec8164.png)
≈ 1.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 101 u (unified atomic mass units) | 101 Da (daltons)](../image_source/0097aa8944fbeed3cf6f337b0e6c571a.png)
Mass of a molecule m from m = M/N_A: | 1.7×10^-22 grams | 1.7×10^-25 kg (kilograms) | 101 u (unified atomic mass units) | 101 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 101](../image_source/482a62adb0fd53b44001b016472db680.png)
Relative molecular mass M_r from M_r = M_u/M: | 101