Input interpretation
![1-(2-fluorophenyl)piperazine monohydrochloride | molar mass](../image_source/f55a3922d2af102e338176002145cd2e.png)
1-(2-fluorophenyl)piperazine monohydrochloride | molar mass
Result
![Find the molar mass, M, for 1-(2-fluorophenyl)piperazine monohydrochloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_10H_14ClFN_2 Use the chemical formula, C_10H_14ClFN_2, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 1 F (fluorine) | 1 C (carbon) | 10 N (nitrogen) | 2 H (hydrogen) | 14 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 1 | 35.45 F (fluorine) | 1 | 18.998403163 C (carbon) | 10 | 12.011 N (nitrogen) | 2 | 14.007 H (hydrogen) | 14 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112 M = 35.45 g/mol + 18.998403163 g/mol + 120.110 g/mol + 28.014 g/mol + 14.112 g/mol = 216.68 g/mol](../image_source/cb8cdbd345ce1894a66d01635bd95e66.png)
Find the molar mass, M, for 1-(2-fluorophenyl)piperazine monohydrochloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_10H_14ClFN_2 Use the chemical formula, C_10H_14ClFN_2, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 1 F (fluorine) | 1 C (carbon) | 10 N (nitrogen) | 2 H (hydrogen) | 14 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 1 | 35.45 F (fluorine) | 1 | 18.998403163 C (carbon) | 10 | 12.011 N (nitrogen) | 2 | 14.007 H (hydrogen) | 14 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112 M = 35.45 g/mol + 18.998403163 g/mol + 120.110 g/mol + 28.014 g/mol + 14.112 g/mol = 216.68 g/mol
Unit conversion
![0.2167 kg/mol (kilograms per mole)](../image_source/e302d6b8cf6bc4e71bd554143a172166.png)
0.2167 kg/mol (kilograms per mole)
Comparisons
![≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/748da788746705d7c153167a19df890c.png)
≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/df9ca70da30a6844e4ad24ae9aa14906.png)
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/d96bea6ef0d5aeceb7109731fe547c94.png)
≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 217 u (unified atomic mass units) | 217 Da (daltons)](../image_source/14990d3440c6b5eead0edd401238799a.png)
Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 217 u (unified atomic mass units) | 217 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 217](../image_source/f297ef3eb15b64879279f9bc0b60dcb9.png)
Relative molecular mass M_r from M_r = M_u/M: | 217