Input interpretation
convert 12 kg of platinum (chemical element) to volume
Results
559.44 mL (milliliters)
Possible intermediate steps
Convert from kilograms into milliliters: 12 kg of Pt (platinum) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 21.45 g/cm^3 (grams per cubic centimeter) at STP of Pt: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(21.45 g) = 559.44 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): Answer: | | (559.44 cm^3)/1 × (1 mL)/(1 cm^3) = 559.44 mL
Unit conversions
5.5944 dL (deciliters)
0.55944 L (liters)
559.44 cm^3 (cubic centimeters)
5.5944×10^-4 m^3 (cubic meters)
2.3646 cups
18.917 fl oz (fluid ounces)
1.1823 pints
0.59115 quarts
0.14779 gallons
Comparisons as volume
≈ ( 0.025 ≈ 1/40 ) × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
≈ volume of a typical human breath ( ≈ 0.5 L )
≈ 8.9 × volume of an Apple iPhone 4 ( ≈ 6.3×10^-5 m^3 )
Comparisons as volume of food or beverage
≈ 0.68 × volume of a US size 2.5 can ( 3.5 cups )
≈ 0.996 × volume of a US size 2 can ( 19 fl oz )
≈ 1.2 × volume of a US vegetable juice can ( 16 fl oz )
Interpretations
volume
volume of food or beverage
section modulus
Basic unit dimensions
![[length]^3](../image_source/e2b7f94768b708ef5fe2b258f6f9aa28.png)
[length]^3
Corresponding quantities
Radius r of a sphere from V = 4πr^3/3: | 51 mm (millimeters) | 0.17 feet | 2 inches
Edge length a of a cube from V = a^3: | 82 mm (millimeters) | 0.27 feet | 3.2 inches
Mass m of water from m = ρ_(H_2O)V: | 559 grams | 1.2 lb (pounds) | (assuming maximum water density ≈ 1000 kg/m^3)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O): | 1.87×10^25 molecules | (assuming maximum water density ≈ 1000 kg/m^3) | (assuming molecular mass of water ≈ 18.02 u)