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volume of 12 kg of platinum

Input interpretation

convert 12 kg of platinum (chemical element) to volume
convert 12 kg of platinum (chemical element) to volume

Results

559.44 mL (milliliters)
559.44 mL (milliliters)

Possible intermediate steps

Convert from kilograms into milliliters: 12 kg of Pt (platinum) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 21.45 g/cm^3 (grams per cubic centimeter) at STP of Pt: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(21.45 g) = 559.44 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): Answer: |   | (559.44 cm^3)/1 × (1 mL)/(1 cm^3) = 559.44 mL
Convert from kilograms into milliliters: 12 kg of Pt (platinum) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 21.45 g/cm^3 (grams per cubic centimeter) at STP of Pt: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(21.45 g) = 559.44 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): Answer: | | (559.44 cm^3)/1 × (1 mL)/(1 cm^3) = 559.44 mL

Unit conversions

5.5944 dL (deciliters)
5.5944 dL (deciliters)
0.55944 L (liters)
0.55944 L (liters)
559.44 cm^3 (cubic centimeters)
559.44 cm^3 (cubic centimeters)
5.5944×10^-4 m^3 (cubic meters)
5.5944×10^-4 m^3 (cubic meters)
2.3646 cups
2.3646 cups
18.917 fl oz (fluid ounces)
18.917 fl oz (fluid ounces)
1.1823 pints
1.1823 pints
0.59115 quarts
0.59115 quarts
0.14779 gallons
0.14779 gallons

Comparisons as volume

 ≈ ( 0.025 ≈ 1/40 ) × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
≈ ( 0.025 ≈ 1/40 ) × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
 ≈ volume of a typical human breath ( ≈ 0.5 L )
≈ volume of a typical human breath ( ≈ 0.5 L )
 ≈ 8.9 × volume of an Apple iPhone 4 ( ≈ 6.3×10^-5 m^3 )
≈ 8.9 × volume of an Apple iPhone 4 ( ≈ 6.3×10^-5 m^3 )

Comparisons as volume of food or beverage

 ≈ 0.68 × volume of a US size 2.5 can ( 3.5 cups )
≈ 0.68 × volume of a US size 2.5 can ( 3.5 cups )
 ≈ 0.996 × volume of a US size 2 can ( 19 fl oz )
≈ 0.996 × volume of a US size 2 can ( 19 fl oz )
 ≈ 1.2 × volume of a US vegetable juice can ( 16 fl oz )
≈ 1.2 × volume of a US vegetable juice can ( 16 fl oz )

Interpretations

volume
volume
volume of food or beverage
volume of food or beverage
section modulus
section modulus

Basic unit dimensions

[length]^3
[length]^3

Corresponding quantities

Radius r of a sphere from V = 4πr^3/3:  | 51 mm (millimeters)  | 0.17 feet  | 2 inches
Radius r of a sphere from V = 4πr^3/3: | 51 mm (millimeters) | 0.17 feet | 2 inches
Edge length a of a cube from V = a^3:  | 82 mm (millimeters)  | 0.27 feet  | 3.2 inches
Edge length a of a cube from V = a^3: | 82 mm (millimeters) | 0.27 feet | 3.2 inches
Mass m of water from m = ρ_(H_2O)V:  | 559 grams  | 1.2 lb (pounds)  | (assuming maximum water density ≈ 1000 kg/m^3)
Mass m of water from m = ρ_(H_2O)V: | 559 grams | 1.2 lb (pounds) | (assuming maximum water density ≈ 1000 kg/m^3)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O):  | 1.87×10^25 molecules  | (assuming maximum water density ≈ 1000 kg/m^3)  | (assuming molecular mass of water ≈ 18.02 u)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O): | 1.87×10^25 molecules | (assuming maximum water density ≈ 1000 kg/m^3) | (assuming molecular mass of water ≈ 18.02 u)