Input interpretation
cupric oxide ⟶ oxygen + copper
Balanced equation
Balance the chemical equation algebraically: ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 ⟶ c_2 + c_3 Set the number of atoms in the reactants equal to the number of atoms in the products for Cu and O: Cu: | c_1 = c_3 O: | c_1 = 2 c_2 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 ⟶ + 2
Structures
⟶ +
Names
cupric oxide ⟶ oxygen + copper
Reaction thermodynamics
Enthalpy
| cupric oxide | oxygen | copper molecular enthalpy | -157.3 kJ/mol | 0 kJ/mol | 0 kJ/mol total enthalpy | -314.6 kJ/mol | 0 kJ/mol | 0 kJ/mol | H_initial = -314.6 kJ/mol | H_final = 0 kJ/mol | ΔH_rxn^0 | 0 kJ/mol - -314.6 kJ/mol = 314.6 kJ/mol (endothermic) | |
Entropy
| cupric oxide | oxygen | copper molecular entropy | 43 J/(mol K) | 205 J/(mol K) | 33 J/(mol K) total entropy | 86 J/(mol K) | 205 J/(mol K) | 66 J/(mol K) | S_initial = 86 J/(mol K) | S_final = 271 J/(mol K) | ΔS_rxn^0 | 271 J/(mol K) - 86 J/(mol K) = 185 J/(mol K) (endoentropic) | |
Chemical names and formulas
| cupric oxide | oxygen | copper Hill formula | CuO | O_2 | Cu name | cupric oxide | oxygen | copper IUPAC name | | molecular oxygen | copper
Substance properties
| cupric oxide | oxygen | copper molar mass | 79.545 g/mol | 31.998 g/mol | 63.546 g/mol phase | solid (at STP) | gas (at STP) | solid (at STP) melting point | 1326 °C | -218 °C | 1083 °C boiling point | 2000 °C | -183 °C | 2567 °C density | 6.315 g/cm^3 | 0.001429 g/cm^3 (at 0 °C) | 8.96 g/cm^3 solubility in water | insoluble | | insoluble surface tension | | 0.01347 N/m | dynamic viscosity | | 2.055×10^-5 Pa s (at 25 °C) | odor | | odorless | odorless
Units
