Input interpretation
![2, 3-dibromobutane | molar mass](../image_source/b1e8f2776b63bfc5642254447b29af14.png)
2, 3-dibromobutane | molar mass
Result
![Find the molar mass, M, for 2, 3-dibromobutane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CH(Br)CH(Br)CH_3 Use the chemical formula, CH_3CH(Br)CH(Br)CH_3, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 2 C (carbon) | 4 H (hydrogen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 2 | 79.904 C (carbon) | 4 | 12.011 H (hydrogen) | 8 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 2 | 79.904 | 2 × 79.904 = 159.808 C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 M = 159.808 g/mol + 48.044 g/mol + 8.064 g/mol = 215.916 g/mol](../image_source/ba0dae95fbea9da36fab6618ca635b45.png)
Find the molar mass, M, for 2, 3-dibromobutane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3CH(Br)CH(Br)CH_3 Use the chemical formula, CH_3CH(Br)CH(Br)CH_3, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 2 C (carbon) | 4 H (hydrogen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 2 | 79.904 C (carbon) | 4 | 12.011 H (hydrogen) | 8 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 2 | 79.904 | 2 × 79.904 = 159.808 C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 M = 159.808 g/mol + 48.044 g/mol + 8.064 g/mol = 215.916 g/mol
Unit conversion
![0.21592 kg/mol (kilograms per mole)](../image_source/d83234c95ebe7cfe705e97f8cdeb3c36.png)
0.21592 kg/mol (kilograms per mole)
Comparisons
![≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/7da31d9835d89476f6a5e26e6c8b68c1.png)
≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/d2daf0a2b91f0c8e72ed60b245adc258.png)
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/12181e6cf5b5ad24326a8a4baacf0c3a.png)
≈ 3.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 216 u (unified atomic mass units) | 216 Da (daltons)](../image_source/ed73be1e3a2242725f39b120dbd32671.png)
Mass of a molecule m from m = M/N_A: | 3.6×10^-22 grams | 3.6×10^-25 kg (kilograms) | 216 u (unified atomic mass units) | 216 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 216](../image_source/671495b54ef895170efb34ccde071c3c.png)
Relative molecular mass M_r from M_r = M_u/M: | 216