Input interpretation
![fluoromethane | molar mass](../image_source/6ef04520bcfb743e89018aca38b24aef.png)
fluoromethane | molar mass
Result
![Find the molar mass, M, for fluoromethane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3F Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 1 F (fluorine) | 1 H (hydrogen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 1 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 3 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 M = 12.011 g/mol + 18.998403163 g/mol + 3.024 g/mol = 34.033 g/mol](../image_source/400f9f5a2a9c1c87bda79e926a0d1b21.png)
Find the molar mass, M, for fluoromethane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3F Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 1 F (fluorine) | 1 H (hydrogen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 1 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 3 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 M = 12.011 g/mol + 18.998403163 g/mol + 3.024 g/mol = 34.033 g/mol
Unit conversion
![0.034033 kg/mol (kilograms per mole)](../image_source/76e98dbd8266d5f231951157435a58e9.png)
0.034033 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.18 ≈ 1/6 ) × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/153fa2aa3f1496c9a9bf7e009ad0ed5d.png)
≈ ( 0.18 ≈ 1/6 ) × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 0.58 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/0cec70e1a3c533bf4fc4bf5852db7df3.png)
≈ 0.58 × molar mass of sodium chloride ( ≈ 58 g/mol )
![≈ 1.9 × molar mass of water ( ≈ 18 g/mol )](../image_source/597c14fc03837110e14f41d8c3f2c6e2.png)
≈ 1.9 × molar mass of water ( ≈ 18 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.7×10^-23 grams | 5.7×10^-26 kg (kilograms) | 34 u (unified atomic mass units) | 34 Da (daltons)](../image_source/4d0296fc06b7a0789e3c6271566d907a.png)
Mass of a molecule m from m = M/N_A: | 5.7×10^-23 grams | 5.7×10^-26 kg (kilograms) | 34 u (unified atomic mass units) | 34 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 34](../image_source/9ad52ef493dea8da14817da1ef1ca341.png)
Relative molecular mass M_r from M_r = M_u/M: | 34