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phenylacetylene-d

Input interpretation

phenylacetylene-d
phenylacetylene-d

Chemical names and formulas

formula | C_6H_5C congruent CD Hill formula | C_8H_5D name | phenylacetylene-d IUPAC name | 2-deuterioethynylbenzene alternate names | 2-deuterioethynylbenzene | (ethynyl-d)benzene mass fractions | C (carbon) 0.932% | H (hydrogen) 0.0684%
formula | C_6H_5C congruent CD Hill formula | C_8H_5D name | phenylacetylene-d IUPAC name | 2-deuterioethynylbenzene alternate names | 2-deuterioethynylbenzene | (ethynyl-d)benzene mass fractions | C (carbon) 0.932% | H (hydrogen) 0.0684%

Lewis structure

Draw the Lewis structure of phenylacetylene-d. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds:  Count the total valence electrons of the carbon (n_C, val = 4) and hydrogen (n_H, val = 1) atoms: 8 n_C, val + 6 n_H, val = 38 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8) and hydrogen (n_H, full = 2): 8 n_C, full + 6 n_H, full = 76 Subtracting these two numbers shows that 76 - 38 = 38 bonding electrons are needed. Each bond has two electrons, so in addition to the 14 bonds already present in the diagram add 5 bonds. To minimize formal charge carbon wants 4 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom:  Fill in the 5 bonds by pairing electrons between adjacent highlighted atoms. Note that the six atom ring is aromatic, so that the single and double bonds may be rearranged: Answer: |   |
Draw the Lewis structure of phenylacetylene-d. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds: Count the total valence electrons of the carbon (n_C, val = 4) and hydrogen (n_H, val = 1) atoms: 8 n_C, val + 6 n_H, val = 38 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8) and hydrogen (n_H, full = 2): 8 n_C, full + 6 n_H, full = 76 Subtracting these two numbers shows that 76 - 38 = 38 bonding electrons are needed. Each bond has two electrons, so in addition to the 14 bonds already present in the diagram add 5 bonds. To minimize formal charge carbon wants 4 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom: Fill in the 5 bonds by pairing electrons between adjacent highlighted atoms. Note that the six atom ring is aromatic, so that the single and double bonds may be rearranged: Answer: | |

3D structure

3D structure
3D structure

Basic properties

molar mass | 103.14 g/mol phase | liquid (at STP) boiling point | 143 °C density | 0.939 g/cm^3
molar mass | 103.14 g/mol phase | liquid (at STP) boiling point | 143 °C density | 0.939 g/cm^3

Units

Liquid properties (at STP)

density | 0.939 g/cm^3 refractive index | 1.548
density | 0.939 g/cm^3 refractive index | 1.548

Units

Non-standard atom properties

H-2 | 1
H-2 | 1

Chemical identifiers

CAS number | 3240-11-7 Beilstein number | 2038975 PubChem CID number | 12198879 PubChem SID number | 24865771 SMILES identifier | C#CC1=CC=CC=C1 InChI identifier | InChI=1/C8H6/c1-2-8-6-4-3-5-7-8/h1, 3-7H/i1D RTECS number | DA0780000 MDL number | MFCD00192389
CAS number | 3240-11-7 Beilstein number | 2038975 PubChem CID number | 12198879 PubChem SID number | 24865771 SMILES identifier | C#CC1=CC=CC=C1 InChI identifier | InChI=1/C8H6/c1-2-8-6-4-3-5-7-8/h1, 3-7H/i1D RTECS number | DA0780000 MDL number | MFCD00192389

Safety properties

flash point | 31.11 °C
flash point | 31.11 °C