mass fractions of yttrium chloride

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yttrium chloride | elemental composition

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$Find the elemental composition for yttrium chloride in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: YCl_3 Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms Cl (chlorine) | 3 Y (yttrium) | 1 N_atoms = 3 + 1 = 4 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction Cl (chlorine) | 3 | 3/4 Y (yttrium) | 1 | 1/4 Check: 3/4 + 1/4 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent Cl (chlorine) | 3 | 3/4 × 100% = 75.0% Y (yttrium) | 1 | 1/4 × 100% = 25.0% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u Cl (chlorine) | 3 | 75.0% | 35.45 Y (yttrium) | 1 | 25.0% | 88.90584 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u Cl (chlorine) | 3 | 75.0% | 35.45 | 3 × 35.45 = 106.35 Y (yttrium) | 1 | 25.0% | 88.90584 | 1 × 88.90584 = 88.90584 m = 106.35 u + 88.90584 u = 195.25584 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction Cl (chlorine) | 3 | 75.0% | 106.35/195.25584 Y (yttrium) | 1 | 25.0% | 88.90584/195.25584 Check: 106.35/195.25584 + 88.90584/195.25584 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent Cl (chlorine) | 3 | 75.0% | 106.35/195.25584 × 100% = 54.47% Y (yttrium) | 1 | 25.0% | 88.90584/195.25584 × 100% = 45.53%$

Find the elemental composition for yttrium chloride in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: YCl_3 Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms Cl (chlorine) | 3 Y (yttrium) | 1 N_atoms = 3 + 1 = 4 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction Cl (chlorine) | 3 | 3/4 Y (yttrium) | 1 | 1/4 Check: 3/4 + 1/4 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent Cl (chlorine) | 3 | 3/4 × 100% = 75.0% Y (yttrium) | 1 | 1/4 × 100% = 25.0% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u Cl (chlorine) | 3 | 75.0% | 35.45 Y (yttrium) | 1 | 25.0% | 88.90584 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u Cl (chlorine) | 3 | 75.0% | 35.45 | 3 × 35.45 = 106.35 Y (yttrium) | 1 | 25.0% | 88.90584 | 1 × 88.90584 = 88.90584 m = 106.35 u + 88.90584 u = 195.25584 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction Cl (chlorine) | 3 | 75.0% | 106.35/195.25584 Y (yttrium) | 1 | 25.0% | 88.90584/195.25584 Check: 106.35/195.25584 + 88.90584/195.25584 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent Cl (chlorine) | 3 | 75.0% | 106.35/195.25584 × 100% = 54.47% Y (yttrium) | 1 | 25.0% | 88.90584/195.25584 × 100% = 45.53%