Search

molar mass of thallium(III) nitrate

Input interpretation

thallium(III) nitrate | molar mass
thallium(III) nitrate | molar mass

Result

Find the molar mass, M, for thallium(III) nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: N_3O_9Tl Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  N (nitrogen) | 3  O (oxygen) | 9  Tl (thallium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  N (nitrogen) | 3 | 14.007  O (oxygen) | 9 | 15.999  Tl (thallium) | 1 | 204.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021  O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991  Tl (thallium) | 1 | 204.38 | 1 × 204.38 = 204.38  M = 42.021 g/mol + 143.991 g/mol + 204.38 g/mol = 390.39 g/mol
Find the molar mass, M, for thallium(III) nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: N_3O_9Tl Use the chemical formula to count the number of atoms, N_i, for each element: | N_i N (nitrogen) | 3 O (oxygen) | 9 Tl (thallium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) N (nitrogen) | 3 | 14.007 O (oxygen) | 9 | 15.999 Tl (thallium) | 1 | 204.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 Tl (thallium) | 1 | 204.38 | 1 × 204.38 = 204.38 M = 42.021 g/mol + 143.991 g/mol + 204.38 g/mol = 390.39 g/mol

Unit conversion

0.39039 kg/mol (kilograms per mole)
0.39039 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.54 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.54 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 6.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 6.7 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 6.5×10^-22 grams  | 6.5×10^-25 kg (kilograms)  | 390 u (unified atomic mass units)  | 390 Da (daltons)
Mass of a molecule m from m = M/N_A: | 6.5×10^-22 grams | 6.5×10^-25 kg (kilograms) | 390 u (unified atomic mass units) | 390 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 390
Relative molecular mass M_r from M_r = M_u/M: | 390